Electricidade is electricity in English
Incident infrared radiation is blocked. Visible and ultraviolet radiation heat Earth. Earth radiates infrared radiation. Infrared radiation is blocked and heats Earth. Visible and shortwave radiation heat Earth.Earth radiates longwave radiationLongwave radiation is reflected downward Longwave radiation <span>heats Earth</span>
To solve this problem we will apply the concepts related to the final volume of a body after undergoing a thermal expansion. To determine the temperature, we will use the given relationship as well as the theoretical value of the volumetric coefficient of thermal expansion of copper. This is, for example to the initial volume defined as , the relation with the final volume as
Initial temperature =
Let T be the temperature after expanding by the formula of volume expansion
we have,
Where is the volume coefficient of copper
Therefore the temperature is 53.06°C
Let the rod be on the x-axes with endpoints -L/2 and L/2 and uniform charge density lambda (2.6nC/0.4m = 7.25 nC/m).
The point then lies on the y-axes at d = 0.03 m.
from symmetry, the field at that point will be ascending along the y-axes.
A charge element at position x on the rod has distance sqrt(x^2 + d^2) to the point.
Also, from the geometry, the component in the y-direction is d/sqrt(x^2+d^2) times the field strength.
All in all, the infinitesimal field strength from the charge between x and x+dx is:
dE = k lambda dx * 1/(x^2+d^2) * d/sqrt(x^2+d^2)
Therefore, upon integration,
E = k lambda d INTEGRAL{dx / (x^2 + d^2)^(3/2) } where x goes from -L/2 to L/2.
This gives:
E = k lambda L / (d sqrt((L/2)^2 + d^2) )
But lambda L = Q, the total charge on the rod, so
E = k Q / ( d * sqrt((L/2)^2 + d^2) )
Answer:
Proof is given below
Explanation:
The length contraction is given by Δx = Δx' *√(1 - v² / c²)
where Δx' is the proper length and is measured in the frame where the object is at rest
Since the y' and z' axes are perpendicular to the direction of motion there is no contraction
So if you let V0 = Δy' * Δz' *Δx'
and V = Δy * Δz * Δx = Δy'* Δz' * Δx
Then
V = V0 * √(1 - v² / c²)