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3 years ago

Put these greenhouse effect events in order, starting with light's origin.

Physics

2 answers:

nordsb [41]3 years ago

4 0

1. Visible and shortwave radiation heat earth.

2. Earth radiates longwave radiation.

3. Longwave radiation is reflected downward.

4. Long wave radiation heats earth.

Fudgin [204]3 years ago

3 0

Incident infrared radiation is blocked. Visible and ultraviolet radiation heat Earth. Earth radiates infrared radiation. Infrared radiation is blocked and heats Earth. Visible and shortwave radiation heat Earth.Earth radiates longwave radiationLongwave radiation is reflected downward Longwave radiation heats Earth

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A neutron star has a mass of 2.0 × 1030 kg (about the mass of our sun) and a radius of 5.0 × 103 m (about the height of a good-s

Nitella [24]

Answer:

$v=516526.9m/s$

Explanation:

The force to which the object of mass m is attracted to a star of mass M while being at a distance r is:

$F=\frac{GMm}{r^2}$

Where $G=6.67\times10^{-11}Nm^2/Kg^2$ is the gravitational constant.

Also, Newton's 2nd Law tells us that this object subject by that force will experiment an acceleration given by F=ma.

We have then:

$ma=\frac{GMm}{r^2}$

Which means:

$a=\frac{GM}{r^2}$

The object departs from rest ( $v_0=0m/s$ ) and travels a distance d, under an acceleration a, we can calculate its final velocity with the formula $v^2=v_0^2+2ad$ , which for our case will be:

$v^2=2ad=\frac{2GMd}{r^2}$

$v=\sqrt{\frac{2GMd}{r^2}}$

We assume a constant on the vecinity of the surface because d=0.025m is nothing compared with $r=5\times10^3m$ . With our values then we have:

$v=\sqrt{\frac{2GMd}{r^2}}=\sqrt{\frac{2(6.67\times10^{-11}Nm^2/Kg^2)(2\times10^{30}Kg)(0.025m)}{(5\times10^3m)^2}}=516526.9m/s$

7 0

3 years ago

Describe the steps in solving the problem below.

12345 [234]

The velocity of the red cart after the collision is 2 m/s

From the law of conservation of momentum, initial momentum of system = final momentum of system.

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.

Substituting the values of the variables into the equation, we have,

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄

4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s

16 kgm/s + 0 kgm/s = 4v₃ + 8 kgm/s

16 kgm/s = 4v₃ + 8 kgm/s

16 kgm/s - 8 kgm/s = (4 kg)v₃

(4 kg)v₃ = 8 kgm/s

Divide both sides by 4 kg, we have

v₃ = 8 kgm/s ÷ 4 kg

v₃ = 2 m/s

The velocity of the red cart after the collision is 2 m/s.

Learn more about conservation of momentum here: