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Elodia [21]
3 years ago
5

EASY POINTS LM is the midsegment of & ABC. If IM is 8 centimeters long, how long is AC

Mathematics
1 answer:
Anika [276]3 years ago
6 0

I think it's 12 because here it comes out

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Help I don't think any of them is the correct answer!
pentagon [3]
I agree with you. I added the mixed numbers and got 4 1/10 and that’s not an option.
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3 years ago
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Find the area of the larger sector.
marin [14]

Answer:

Step-by-step explanation:

area of circle = πr² = 25π ft²

area of sector = 25π × 221°/360° ≅ 48.21 ft²

4 0
3 years ago
What is the value of x in 40,000 mg = 10x g? Please answer quick!
Paul [167]
1g = 1000mg

40,000mg = 40g

10xg=40g

X=4

Hope this helps.
5 0
3 years ago
Help, please giving brainless
podryga [215]

Step-by-step explanation:

Number of boxes that will fit =2340

Step-by-step explanation:

The shipping box volume can be calculated by the formula V = Lxwxh ,where L ,w ,h are length ,width and height of the box.

The length of the shipping box =3\frac{3}{4} =\frac{15}{4} ft.

Width = 3 ft.

Height =3\frac{1}{4} =\frac{13}{4} ft.

Volume of shipping box =\frac{15}{4} .3 .\frac{13}{4} =\frac{585}{16} = 36.6 ft.cubic ft.

Volume of shipping box can also be calculated by multiplying base area with the height of box.

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Volume of box = base area x height =\frac{45}{4} .\frac{13}{4} = 36.6 cubic ft.

Volume of packing cubes =\frac{1}{4} .\frac{1}{4} .\frac{1}{4} =\frac{1}{64} cubic ft.

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4 0
3 years ago
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Tall Club International has a requirement that women must be at least 70 inches tall. Given that women have normally distributed
Marizza181 [45]

Answer:

0.0150 = 1.50% of women satisfy that height requirement.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 63.7, \sigma = 2.9

Find the percentage of women who satisfy that height requirement.

This is 1 subtracted by the pvalue of Z when X = 70. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 63.7}{2.9}

Z = 2.17

Z = 2.17 has a pvalue of 0.9850

1 - 0.9850 = 0.0150

0.0150 = 1.50% of women who satisfy that height requirement.

8 0
3 years ago
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