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2 years ago

1. Write the linear equation for a line with a slope of 1/2 that goes through the point (-1, 0).

Mathematics

1 answer:

svetlana [45]2 years ago

6 0

Answer:

uhuhhubuggyugyug

uiyuyuh

jhjhh

Step-by-step explanation:

y7gukgyfkjiyfikyutgikuygtujki

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Rectangle PQRS has vertices at P(3,5), Q(8,5), R(8,0) and S. The coordinates of point S are

pashok25 [27]

I would have guessed point S is (3,0).

7 0

2 years ago

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Add and Subtract Rational Expressions with a Common Denominator

Sladkaya [172]

Answer:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}$

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}$

Operating on the numerators:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}$

Removing parentheses:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}$

Simplifying:

$\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}$

The expression cannot be further simplified.

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2 years ago

Anyone know the answer to this?

jeyben [28]

3x-5+19-x+2x
5x-x=14
4x=14

3 0

3 years ago

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I WILL GIVE BRAINLIEST!!

vlabodo [156]

The answer is the square root of 4.

2 * 2 = 4

2 is a rational number; therefore, the square root of 4 is a rational number.

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3 years ago

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Solve the indicated variable 2(3n+4)=5n+8

Svetlanka [38]

N=0 is the answer for this problem

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3 years ago