We base ourselves in the one piece of crucial evidence: She has 2 quarters.
-from the rest of the problem, we know that she has 2 more NICKEL'S than QUARTERS,
(2 Quarters + 2 = 4 nickels)
she has 3 fewer nickels than dimes,
DIME - 3 = Nickels
D - 3 = 4
D = 7
7 dimes
(70 cents)
4 nickels
(20 cents)
2 quarters
(25 cents)
115 cents
or $1.15
Answer:
y=1/3x-8
Step-by-step explanation:
let me know if not clear
Answer:
One solution.
Step-by-step explanation:
3(x + 9) = 2x + 54
3x + 27 = 2x + 54
3x + 27 - 2x = 2x + 54 - 2x
x + 27 = 54
x + 27 - 27 = 54 - 27
x = 27
Answer: 81%
Step-by-step explanation:
From the question, we are informed that a student received the following test scores: 71%, 89%, 72%,
84% and 83% in 5 tests and the student wants to maintain an average of 80%.
The lowest score/grade they can receive on the next test to maintain at least an 80% average first thus:
First, to make it easy we can remove the percent sign. Then we multiply 80 by 6 since we're calculating for 6 tests scores. This will be:
= 80 × 6
= 480
We then add all the 5 test scores. This will be:
= 71 + 89 + 72 + 84 + 83
= 399
We then subtract the values gotten. This will be:
= 480 - 399
= 81
This means the student must get at least 81%
I believe it is zero, because there is no number less than 1.
