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Westkost [7]
2 years ago
6

Two groups went hiking, leaving at the same time and arriving back at the same time. While one group moved away at the speed 6 m

ph and then moved back at the speed 4 mph, the other group moved all the way with the same speed. What was the speed of this second group, if both groups covered the same total distance, 24 miles?
Mathematics
1 answer:
Evgesh-ka [11]2 years ago
5 0

Step-by-step explanation:

d = the distance in one direction.

the time t1 it took group 1 was

t1 = d/6 + d/4

and t2 for group 2 moving with speed2 all the way

t2 = (d+d)/speed2

we know

2d = 24 miles

d = 12 miles

t1 = t2

so,

12/6 + 12/4 = 24/speed2

2 + 3 = 24/speed2

5 = 24/ speed2

5×speed2 = 24

speed2 = 24/5 = 4.8 mph

the second group moved with 4.8 mph.

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The multiplication table below can be used to find equivalent ratios.
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Answer:

c

Step-by-step explanation:

3/24 = 3/3*8 = 1/8

24/32 = 4*6/4*8 = 6/8

32/24 = 4*8/4*6 = 8/6

24/3 = 3*8/3 = 8/1 = 8

5 0
2 years ago
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The school baseball team has 3 pitchers. How many different 3-player pitching schedules can the coach choose from?
expeople1 [14]

Answer:

6 schedules

Step-by-step explanation:

First, decide if this situation describes a combination or a permutation by looking at the significance of order. Consider a specific example where the letters A – C represent the 3 different pitchers. The pitching order A, B, C is different from the pitching order B, C, A because the players will be pitching at different times. Therefore, this situation describes a permutation. Use the formula for finding the number of permutations when the number of pitchers is 3, so n = 3, and all 3 are taken at a time, so r = 3 as well.

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Express 0.1201201 in p/q form
Helen [10]

Answer:

Step-by-step explanation:

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3 0
3 years ago
Who is the most beautiful woman in the world. Also attach her picture.
ANEK [815]

Answer:

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3 years ago
In the circle shown below T is the center of the circle, and segments PN and SQ are diameters, and segment PR is tangent to the
alina1380 [7]
Angle SQN = 66 degrees (given)
----------------------------
Use the inscribed angle theorem to get

Minor Arc SN = 2*(angle SQN)
Minor Arc SN = 2*(66)
Minor Arc SN = 132 degrees
----------------------------
Arc PSN is a semicircle so it is 180 degrees, meaning that...

Arc PSN = (minor arc PS) + (minor arc SN)
180 degrees = (minor arc PS) + (132 degrees)
180 = (minor arc PS) + 132
180 - 132 = (minor arc PS) + 132 - 132
48 = minor arc PS
minor arc PS = 48 degrees
central angle RTP = minor arc PS = 48 degrees
----------------------------
Focus on triangle PTR; isolate angle PRT

(angle TPR) + (angle PRT) + (angle RTP) = 180
(90) + (angle PRT) + (48) = 180
(90+48) + (angle PRT) = 180
138 + (angle PRT) = 180
138 + (angle PRT) - 138 = 180 - 138
angle PRT = 42 degrees
----------------------------
----------------------------
Final Answer: 
The measure of angle PRT is 42 degrees

8 0
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