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Likurg_2 [28]
2 years ago
10

Set a = 3 and k = 1. Use the slider to manipulate M. What happens to the graph when M is negative?

Mathematics
1 answer:
ANEK [815]2 years ago
5 0

Answer:

C (reflection across the x access)

Step-by-step explanation:

I got it right on edge

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A football team gained 9 yards on one play and then lost 22 yards on the next.Write a sum of integers to find theoverral change
anastassius [24]

Answer:

-13 yards

Step-by-step explanation:

Estimating that we start off on the middle line, we could solve this by simply looking at a number line. Moving 9 yards ahead would put us at 9. But moving  back 22 would place us at a negative number. An easy way of doing this is subtracting 9 from 22:

22 - 9 = 13

But, we already know that since the answer is to the left of zero, it will be a negative number. So we flip the sign to get -13 yards.

3 0
3 years ago
A tennis ball travels at speed of 120 miles per hour.convert this rate to feet per second
Vanyuwa [196]
120\frac{mile}{hour}\\\\
1 \ mile=5280\ feet\\
1\ hour=3600\ seconds\\\\
120\frac{mile}{hour}=120*\frac{5280}{3600}=\frac{120*5280}{3600}=\frac{633600}{3600}=176\frac{feet}{second}\\\\
\boxed{120\frac{mile}{hour}=176\frac{feet}{second}}
4 0
2 years ago
A recipe for lemonade calls for 1 cup of sugar and 6 cups of water. How much sugar is used per cup of water?
grandymaker [24]
The answer is 1/6, or .16666...
3 0
2 years ago
Can someone tell me what to do
vodka [1.7K]
Show me a picture of the grid. (The square with the lines)
3 0
3 years ago
Find all values of x for which the series converges. (Enter your answer using interval notation.) [infinity] 9 x − 7 9 n n = 0 F
makkiz [27]

Answer:

The series converges to   $ \frac{1}{1-9x} $     for   $ \frac{-1}{9} < x < \frac{1}{9} $                

Step-by-step explanation:

Given the series is     $ \sum_{n=0}^{\infty} 9^n x^n $

We have to find the values of x for which the series converges.

We know,

$ \sum_{n=0}^{\infty} ar^{n-1} $ converges to  (a) / (1-r) if r < 1

Otherwise the series will diverge.

Here, $ \sum_{n=0}^{\infty} 9^n x^n =  \sum_{n=0}^{\infty} (9x)^{n}  $ is a geometric series with |r| = | 9x |

And it converges for |9x| < 1

Hence, the given series gets converge for $ \frac{-1}{9} < x < \frac{1}{9} $

And geometric series converges to $ \frac{a}{1-r} $

Here, a = 1 and r = 9x

Therefore, $ \frac{a}{1-r} = \frac{1}{1-9x} $

Hence, the given series converges to   $ \frac{1}{1-9x} $     for   $ \frac{-1}{9} < x < \frac{1}{9} $

4 0
3 years ago
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