10 1/2 =
10/1 + 1/2=
2/2 (10/1) + 1/2=
20/2 + 1/2=
21/2
Answer:
0ft and 60ft
Step-by-step explanation:
Given
The attached function
Required
Determine the valid values of the domain of the function
To do this, we simply consider the starting point and the end point of the trajectory on the x-axis (i.e. the horizontal distance).
From the attached graph, the horizontal distance starts from 0 and ends at 180.
This implies that the domain is: 
From the options, the values that fall in this bracket are 0ft and 60ft
Answer: Let's solve your equation step-by-step.
2h−3=3
Step 1: Add 3 to both sides.
2h−3+3=3+3
2h=6
Step 2: Divide both sides by 2.
2h/2 = 6/2
h = 3.
Multiply 81.5p and divide 7.5% you get the answer
Answer:

Step-by-step explanation:

![Hence,\\As\ Angle\ A\ and\ Angle\ B\ are\ co-interior\ angles, if\ they\ are\\ supplementary\ then\ AD \parallel BC.\ Lets\ check\ that\ out.\\Hence,\\Angle\ A=2x=2*15=30\\Angle\ B=90\ [Given]\\Hence,\\As\ 90+30\neq 180,\\Angle\ A +Angle\ B\neq 180\\Hence,\\As\ Angle\ A and\ Angle\ B\ are\ not\ supplementary, AD\ will\ not\ be\ parallel\ to\ CB.](https://tex.z-dn.net/?f=Hence%2C%5C%5CAs%5C%20Angle%5C%20A%5C%20and%5C%20Angle%5C%20B%5C%20are%5C%20co-interior%5C%20angles%2C%20if%5C%20they%5C%20are%5C%5C%20supplementary%5C%20then%5C%20AD%20%5Cparallel%20BC.%5C%20Lets%5C%20check%5C%20that%5C%20out.%5C%5CHence%2C%5C%5CAngle%5C%20A%3D2x%3D2%2A15%3D30%5C%5CAngle%5C%20B%3D90%5C%20%5BGiven%5D%5C%5CHence%2C%5C%5CAs%5C%2090%2B30%5Cneq%20180%2C%5C%5CAngle%5C%20A%20%2BAngle%5C%20B%5Cneq%20180%5C%5CHence%2C%5C%5CAs%5C%20Angle%5C%20A%20and%5C%20Angle%5C%20B%5C%20are%5C%20not%5C%20supplementary%2C%20%20AD%5C%20will%5C%20not%5C%20be%5C%20parallel%5C%20to%5C%20CB.)