Which three side lengths best describe the triangle in the diagram?
1 answer:
The three side length that describes the triangle in the image attached below are: 5 cm, 12 cm, and 13 cm.
<h3>What is a Triangle?</h3>A triangle is a shape that has three sides. The sides can be measured using a ruler.
The sides of the triangle in the image shown have side lengths as measured by the ruler beside each of the sides, which are 5 cm, 12 cm, and 13 cm.
Therefore, the three side lengths of the triangle in the diagram are: 5 cm, 12 cm, and 13 cm.
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The standard equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is
9514 1404 393
Answer:
38.5°
Step-by-step explanation:
A triangle solver can give an answer easily. The angle is 38.5°.
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The law of cosines can be written to solve for an unknown angle C opposite side 'c' and flanked by sides 'a' and 'b'.
C = arccos((a² +b² -c²)/(2ab))
Here, we have a=35, b=48, c=30, so the angle is ...
C = arccos((35² +48² -30²)/(2·35·48)) = arccos(2629/3360) ≈ 38.515°
The angle the cable makes with the pole is about 38.5°.
Answer:
Step-by-step explanation:
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