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3 years ago

Which of the following coordinate planes shows the graph of the function y-3=-2(x+2)?

Mathematics

1 answer:

Ugo [173]3 years ago

8 0

Answer:

-5=x

Step-by-step explanation:

3=-2 (x+2)

-2 (x+2) = -2x-4

3=-2x-4

-4 from 3 and -4

= -7=-2x

do the opposite "-2 to +2 "

=-5=x

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The question is: "Without actually graphing, describe how the graph of y = ( -2^(x+17) ) - 4.3 is related to the graph of y = 2^

Alexxx [7]

Answer:

The function has been flipped due to the negative in front.

The function has been shifted 17 units to the left.

The function has been shifted 4.3 units down.

Step-by-step explanation:

When functions are transformed there are a few simple rules:

• Adding/subtracting inside the parenthesis to the input shifts the function left(+) and right(-).

• Adding/subtracting outside the parenthesis to the output shifts the function up(+) and down(-).

• Multiplying the function by a number less than 1 compresses it towards the x-axis.

• Multiplying the function by a number greater than 1 stretches it away from the x-axis.

The graph of $(-2^{x+17}) -4.3$ compares to $2^x$ in the following ways:

The function has been flipped due to the negative in front.

The function has been shifted 17 units to the left.

The function has been shifted 4.3 units down.

5 0

3 years ago

One sixth of forty-two is seven.<br> How do I write out the equation for that?

sertanlavr [38]

Answer:

Step-by-step explanation:

1/6 * 42 = 7

"of" means multiply

"is" means =

6 0

2 years ago

When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain con

marusya05 [52]

Answer: The mass of the object is 10 kg

Step-by-step explanation:

According to Newton's second law of motion, the force $F$ applied to an object with mass $m$ is directly proportional to its acceleration $a$ :

$F=ma$ (1)

If we isolate $a$ :

$a=\frac{F}{m}$ (2) This means the acceleration of the object varies inversely with its mass

Now, we are given the following data to calculate a constant force using (1):

$m_{1}=4 kg$

$a_{1}=5 m/s^{2}$

$F=m_{1}a_{1}$ (3)

$F=(4 kg)(5 m/s^{2)$ (4)

$F=20 N$ (5)

If we apply this same force calulated in (4) in another object with an acceleration of $a_{2}=2 m/s^{2}$ , its mass $m_{2}$ will be:

$F=m_{2}a_{2}$ (6)

$20 N=m_{2}2 m/s^{2}$ (7)

Finding $m_{2}$ :

$m_{2}=10 kg$ This is the mass of the object

4 0

3 years ago

Which statement is true about the graphs of the two lines y = –6 and x =1/6 ?

sweet-ann [11.9K]

These lines are perpendicular because y = -6 is a horizontal line with a slope of 0 and x = 6 is a vertical line with an undefined slope

6 0

3 years ago

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What is the answer of equation 9x(30+7)=(9x30)+(9x7)

RSB [31]

(9x30) =270 (9x7) =63

Distributive Property

5 0

3 years ago

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