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ddd [48]
2 years ago
12

What is the value of n? 38°

Mathematics
1 answer:
oee [108]2 years ago
4 0

Answer: 247 the Answer

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Yasmin swims at a constant rate of 2 km/h for 2.5 h. How far does Yasmin swim? 4.5 km 5 km 6 km 6.5 km
Neporo4naja [7]
She swims for 2.5 hours at a rate of 2 km/hr
Multiply 2.5 * 2 = 5 km
3 0
3 years ago
At a college campus, random drug tests are carried out to prevent use of prohibited drugs by athletes. Of all the athletes on ca
saw5 [17]

Answer:

a) 0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

b) 0.2693 = 26.93% probability that this drug user never used the prohibited drug.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

A. If an athlete is selected at random, what is the probability that athlete will test positive for prohibited drug use?

100 - 5 = 95% of 8%

100 - 13 = 87% of 17%

11% of 75%

So

p = 0.95*0.08 + 0.87*0.17 + 0.11*0.75 = 0.3064

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

B. If an athlete tests positive after a drug test, what is the probability that this drug user never used the prohibited drug?

Conditional Probability

Event A: Tests Positive

Event B: Never used the drug.

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use

This means that P(A) = 0.3064

Probability of testing positive while never using the drug.

11% of 75%. So

P(A \cap B) = 0.11*0.75 = 0.0825

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0825}{0.3064} = 0.2693

0.2693 = 26.93% probability that this drug user never used the prohibited drug.

8 0
3 years ago
True or False? The following is an example of inductive reasoning: In your study of geometry, you notice that every square you h
dimulka [17.4K]
I believe this is true
5 0
4 years ago
Read 2 more answers
An airplane with a speed of 120 knots is headed west while a 30-knot wind is blowing from 120°. Find the ground speed to the nea
SVEN [57.7K]

Answer:

Velocity of the plane relative to the ground

= [(-145.98î) + (15j)] knots

Magnitude = groundspeed = 146.75 knots

Direction = -5.9°

Step-by-step explanation:

This is a relative velocity question.

Let the velocity of the airplane relative to the wind be V(aw)

Velocity of the airplane relative to the ground = Va

The velocity of the wind relative to the ground = Vw

The relative velocity theory enables us o relate these as thus,

V(aw) = Va - Vw

Va = V(aw) + Vw

V(aw) = (-120î) knots (120 west)

For Vw, the wind is said to be blowing from 120°, reading this on a three figure bearing as angle from the north,

This gives the real direction of the wind to be 150° from the positive x-axis as shown in the attached image.

Vw = (30cos 150°)î + (30sin 150°)j

Vw = (-25.98î + 15j) knots

Va = V(aw) + Vw = (-120î) + (-25.98î + 15j)

Va = (-145.98î) + (15j)

Magnitude of Va = √[(-145.98)² + (15)²] = 146.75 knots

Direction = tan⁻¹ (-15/145.98) = -5.9°

Hope this Helps!!!

3 0
4 years ago
N + 6 < -1 what is the solution to the inequality
Mashcka [7]

Answer:

N<-7 or (-∞,-7) hope this helps

4 0
3 years ago
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