because its isosceles so 9+9=x²
and x equal
2√3
Theory:
The standard form of set-builder notation is <span>
{ x | “x satisfies a condition” } </span>
This set-builder notation can be read as “the set
of all x such that x (satisfies the condition)”.
For example, { x | x > 0 } is
equivalent to “the set of all x such that x is greater than 0”.
Solution:
In the problem, there are 2 conditions that must
be satisfied:
<span>1st: x must be a real number</span>
In the notation, this is written as “x ε R”.
Where ε means that x is “a member of” and R means “Real number”
<span>2nd: x is greater than or equal to 1</span>
This is written as “x ≥ 1”
Answer:
Combining the 2 conditions into the set-builder
notation:
<span>
X =
{ x | x ε R and x ≥ 1 } </span>
Answer:
1080
Step-by-step explanation:
PEMDAS says multiply and divide from left to right
9*5*6*3÷3*4*6÷6
45*6*3÷3*4*6÷6
270*3÷3*4*6÷6
810÷3*4*6÷6
270*4*6÷6
1080*6÷6
6480÷6
1080
Answer:
(x-y) (a+x-y)
Step-by-step explanation:
(y-x)=-(x-y)
-a(y-x) = a(x-y)
(x-y)^2 = (x-y)(x-y)
(x-y)(a + x - y)
Answer:
I just need popints
Step-by-step explanation:
I just need points
