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11Alexandr11 [23.1K]
1 year ago
7

The measure of angle is 0 is 7pi/4. The measure of its reference angle is ___ °, and tan 0 is ____

Mathematics
1 answer:
ollegr [7]1 year ago
7 0

Answer: pi/4 and -1

Step-by-step explanation:

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How many 5/6 are in 2/3
Nitella [24]
The answer is 0.5 repeating
4 0
3 years ago
Read 2 more answers
If another line is perpendicular to the line shown on the graph, what must be its slope
Shtirlitz [24]

It's B

Slope is negative, the other must be positive due to m1 x m2 = - 1

m1 = -2/5

The diagram shows a gradient of -2/5. So, the

reciprocal of this valve to make - 1 is 5/2 (which is the - 2/5 flipped upside down, but positive)

-2/5 x 5/2 = - 10/10 (or - 1)

Thus, the perpendicular line to this has a gradient of 5/2.

Hope this helps!

4 0
1 year ago
Solve for x 2x/3 +1 =3
Bess [88]

Answer:

x=3

Step-by-step explanation:

Hello,

The first thing you do is set up your equation, and we are solving for x so we are going to get x by itself on one side of the = sign.

       2x/3+1=3        First thing: subtract 1 from BOTH sides.

               -1  -1

----------------------

          2x/3=2       Multipliy by 3 on both sides

              *3 *3

-----------------------

            2x=6         Divide by 2 on both sides

             /2 /2

-----------------------

           x=3

I hope this helped you!!!

5 0
3 years ago
I need help on Area plz
nydimaria [60]

Answer:139 cm squared

Step-by-step explanation:

First separate it:

10x3

7x7

4x15

These are the 3 rectangles that make up this shape

Then multiply

10x3=30

7x7=49

4x15=60

Then add your answers

30+49+60=139cm squared

8 0
3 years ago
Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.
Mama L [17]

Multiplying both sides by y^2 gives

xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1

so that substituting v=y^3 and hence \frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx} gives the linear ODE,

\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1

Now multiply both sides by 3x^2 to get

x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2

so that the left side condenses into the derivative of a product.

\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2

Integrate both sides, then solve for v, then for y:

x^3v=\displaystyle\int3x^2\,\mathrm dx

x^3v=x^3+C

v=1+\dfrac C{x^3}

y^3=1+\dfrac C{x^3}

\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}

6 0
3 years ago
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