Q25 is D, Q26 is A, & Q28 is 6. Sorry, I'm not sure how to calculate Q27
Answer:What was done from the first to the second equation was that the fraction was simplified. 126 and 32 have a common factors of 2.
126/32=(63*2)/(16*2)
The 2s in the top and bottom can cancel out, leaving the fraction 63/16.
In addition, since there are x terms on the top and bottom, they cancelled out as well.
x/x^3=1/x^2
This leaves an x^2 term on the bottom.
Thus, if a is 16, and b is 2, you will have an equivalent form of the fraction.
Step-by-step explanation:
Answer:
y = 2x + 4
y = 2x + 46x – 3y = -12
y = 2x + 46x – 3y = -12And
y = 2x + 46x – 3y = -12Andy = 2x
y = 2x + 46x – 3y = -12Andy = 2x-8x – 2y = 24
Step-by-step explanation:
hope it helps you
Answers:
- x = 7
- Area of shaded region = 162 square units
You may need to leave off the "square units" portion.
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Explanation:
For now, ignore the smaller rectangle and its dimensions. The larger rectangle has sides 3x and x+5, which I'll call the length and width.
L = 3x
W = x+5
The perimeter of any rectangle is P = 2(L+W). Plug in those values of L and W, and also the given perimeter P = 66. Isolate x.
P = 2(L+W)
2(L+W) = P
2(3x+x+5) = 66
2(4x+5) = 66
8x+10 = 66
8x = 66-10
8x = 56
x = 56/8
x = 7
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Now that we know x, we can find the area of the rectangles.
As you probably can guess, the shaded region is the difference of the two areas.
A = area of larger rectangle
A = (length)*(width)
A = (3x)*(x+5)
A = (3*7)*(7+5)
A = 252
B = area of smaller rectangle
B = (x+3)*(x+2)
B = (7+3)*(7+2)
B = 90
C = area of shaded region
C = A - B
C = 252 - 90
C = 162 square units is the area of the shaded region.
The answer is 36ft to the second power which is A.
