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2 years ago

Evaluate the function

Mathematics

1 answer:

vova2212 [387]2 years ago

4 0

-1 you change all the x values to -1 and then solve

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The cost of fencing a circular field at the rate of Rs.24 per metre is Rs. 5280.

7nadin3 [17]

Answer:

radius = 35.03 m

Step-by-step explanation:

5280/24 = circumference = 220 m

220 /Pi = diameter = 70.06 m

70.06/2 = radius = 35.03 m

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1 year ago

Describe the relationship between the terms in each arithmetic sequence. Then write the next three terms in each sequence.

11111nata11111 [884]

Answer:

For the first one: they increase in by 14, so the three could be 73,87,101

Second: Sequential, increasing by 20, next could be 110, 130, 150

Third: Increase by 27, next three could be 122,149,176

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2 years ago

Suppose that 5% of the time Todd attends a concert twice a month, 40% of the time he attends a concert once a month, and 55% of

alexira [117]

it’s the right answer anyways hope u pass all your classes thanks bye now purrr 1245/4849

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2 years ago

A bag contain 3 black balls and 2 white balls.

Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

$Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\$

$Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}$

Probability of at least one black( means BB or BW or WB)

$=\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}$

Probability of at most one black ( means WW or WB or BW)

$=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}$

a) Probability both black without replacement

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

b) Probability of one black and one white

$=\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}$

c) Probability of at least one black ( BB or BW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}$

d) Probability of at most one black ( BW or WW or WB)

$=\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}$

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2 years ago

Can you find out a harder question my child is so smart I can’t keep up with her

zloy xaker [14]

Answer:

what they currently going over?

5 0

2 years ago

Read 2 more answers