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KatRina [158]
1 year ago
11

Given the function h of x equals three times the square root x plus 1 end root minus 2, which statement is true about h(x)?

Mathematics
1 answer:
topjm [15]1 year ago
8 0

A function assigns the values. The correct option is D.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

The given function h(x)=3(\sqrt{x+1})-2 when plotted on the graph will look as shown below. Therefore, the function is increasing on the interval (–1, ∞).

Hence, the correct option is D.

Learn more about Function:

brainly.com/question/5245372

#SPJ1

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It should be "A"

On the number line, it shows that -4.5 is further and to the right of -2.3.

Hope that helps!
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What is not an acceptable form of proof
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Simplify the expression. (3x2 – 4x + 1) + (-x2 + x – 9)
LuckyWell [14K]

(3x^2 - 4x + 1) + (-x^2 + x - 9)=\\3x^2-4x+1-x^2+x-9=\\2x^2-3x-8

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Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1, and the zeros 4 and 3−
Neko [114]

Answer:

P(x) = x^3 - 10x^2+ 34x-40

Step-by-step explanation:

Given

p =1 -- Leading coefficient

Zeros: 4\ and\ 3  - i

Required

Determine the polynomial

Represent the zeros with a and b

Such that

a = 4

b = 3 - i

The polynomial is:

P(x) = p * (x - a) * (x - b)

P(x) = 1 * (x - 4) * (x - (3 - i))

However, to solve further: We need to symmetrise over 3-i  and its conjugate

P(x) = 1 * (x - 4) * (x - (3 - i))* (x - (3 + i))

P(x) =  (x - 4) * (x - (3 - i))* (x - (3 + i))\\\\

To define a suitable function, the expression becomes

P(x) =  (x - 4) * ((x - 3)^2+1)

P(x) =  (x - 4) * ((x - 3)(x - 3)+1)

P(x) =  (x - 4) * (x^2 - 6x + 9+1)

P(x) =  (x - 4) * (x^2 - 6x +10)

Open bracket

P(x) = x^3 - 6x^2 +10x - 4x^2 + 24x-40

P(x) = x^3 - 6x^2  - 4x^2+10x + 24x-40

P(x) = x^3 - 10x^2+ 34x-40

5 0
2 years ago
Image 1<br>image 2<br>image 3<br>none ​
Talja [164]
I’d assume image 1 since it’s a combination of multiple substances or a mixture.
7 0
2 years ago
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