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hichkok12 [17]
2 years ago
15

If I get a 100 on one assingment and a 57 on the other, what is my average of the assignments?

Mathematics
2 answers:
MakcuM [25]2 years ago
7 0

Answer:

78.5

Step-by-step explanation:

Add the two scores, and then divide this sum by 2 to obtain the average score:

\frac{100 + 57}{2}  =  \frac{157}{2}  = 78.5

Galina-37 [17]2 years ago
7 0

Answer:

78.5

Step-by-step explanation:

To calculate the average of the assignments, you must find the mean of the assignments.

Mean = sum of the items divided by the number of items

\frac{100+57}{2}

=\frac{157}{2}

=78.5

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musickatia [10]

Answer:

a) The probability of selling less than 100 gallons (x≤1) is P=0.16.

b) The mean number of gallons is M=80 gallons.

Step-by-step explanation:

The probability of selling x, in hundred of gallons, on any day during the summer is y(x)=0.32x, in a range for x from [0;2.5].

The probability of selling less than 100 gallons (x≤1) is then:

P(x\leq1)=\int_0^{100}0.32x\cdot dx\\\\P(x\leq1)=0.16(x_b^2-x_a^2)\\\\P(x\leq1)=0.16(1^2-0^2)=0.16

The mean number of gallons can be calculated as:

M=\int_0^{2.5}(y(x)/x)\cdot dx=\int_0^{2.5}(0.32)\cdot dx\\\\M=0.32(x_b-x_a)=0.32(2.5-0)=0.32*2.5=0.8

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2 years ago
Is 5/11 closer to 0, 1, 1/2
Levart [38]

Answer:

If your rounding up, its 1/2

Step-by-step explanation:

6 0
3 years ago
Cindy’s Fish Cam video data showed that for every 100 fish she saw in the deep habitat, there were 315
Setler79 [48]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Please help me with this sum​
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Answers:

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8 0
2 years ago
A line passes through (−1, 7) and (2, 10).
Murljashka [212]
The formula is y=mx+b
To get the slope or m, use this formula
(the second y minus the first y)/(the second x minus the first x)
Now set it up.
(10-7)/(2--1)
3/3=slope is 1.
y=1x+b

Insert one of the points for x and y.
i will do (-1,7)
7=1(-1)+b
7=-1+b
8=b
Insert this into the final equation:
y=1x+8

Try it out. If you're not sure, try both points. If it works, then you set it up correctly.
6 0
3 years ago
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