4a5+28+6b7-30
4a5+6b7-2<—- this is a to the power of 5 , b to the power of 7
(Is that 5a or a to the power of 5 )
20a+28+42b-30
20a+42b-2<—— this is 5a , 7b
I think it’s $34 but i’m not sure
Answer:
4<C
<10
Step-by-step explanation:
Theorem: Given a triangle with sides A, B and C the sum of the lengths of any two sides of a triangle must be greater than the third side:
1. A+B>C
2. B
+C
>A
3. A+C>B
Thus given two sides of A=3 and B=7 C can be:
7
−3<C
<
7+3
C range
4<C
<10
Answer:
Step-by-step explanation:
we have
we know that
substitute
