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olga_2 [115]
4 years ago
8

(9,-9)

Mathematics
2 answers:
uysha [10]4 years ago
8 0

Answer:

g

Step-by-step explanation:

erik [133]4 years ago
5 0

Answer:

                               

Step-by-step explanation:

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What shapes has parallel sides only​
olga2289 [7]

Square, Rectangle and Rhombus

5 0
3 years ago
What is the value of x in x+y=-10 and x-y=2
loris [4]

Answer:

x = -4

Step-by-step explanation:

x+y = -10 -------- (1)

x-y = 2 ------- (2)

from (1)

x+y = -10

y = -10-x -------- (3)

substitute (3) into (2)

x-y = 2

x-(-10-x) = 2

x+10+x = 2

2x = 2-10

2x = -8

x = -8/2

x = -4

6 0
3 years ago
Read 2 more answers
Your are part of a team studying an endangered species of land snail in upstate New York. You and your colleagues capture and ma
ELEN [110]

Answer:

720 individuals

Step-by-step explanation:

According to my research, I can say that based on the information provided within the question you can conclude that the population of land snails has about 720 individuals. We can calculate this by using the Rule of Three formula that is attached below.

 x   ⇒   80 marked

45   ⇒   5 marked

\frac{45*80}{5} = x

720= x

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0
3 years ago
Read 2 more answers
The greatest common factor using prime factorization for 28 and 63
Degger [83]
The answer is seven im sure

7 0
4 years ago
Read 2 more answers
please solve it please solve it please solve it please solve it please solve it please solve it please solve it please solve it
katovenus [111]

Since \alpha and \beta are roots of ax^2+bx+c, we can factorize the quadratic in terms of the roots as

ax^2+bx+c = a(x-\alpha)(x-\beta)

Expanding the right side gives

ax^2+bx+c = ax^2-a(\alpha+\beta)x+a\alpha\beta

so that

\alpha + \beta = -\dfrac ba \\\\ \alpha\beta = \dfrac ca

A polynomial with roots \alpha^2 and \beta^2 would be

(x-\alpha^2)(x-\beta^2)

and expanding this gives

x^2 - (\alpha^2+\beta^2)x+\alpha^2\beta^2

Now,

\alpha\beta = \dfrac ca \implies \alpha^2\beta^2 = (\alpha\beta)^2 = \dfrac{c^2}{a^2}

and

(\alpha+\beta)^2 = \alpha^2 + 2\alpha\beta + \beta^2 \\\\ \implies \alpha^2+\beta^2 = \left(-\dfrac ba\right)^2 -2\left(\dfrac ca\right) = \dfrac{b^2-2ac}{a^2}

So we can write the second quadratic in terms of a,b,c as

(x-\alpha^2)(x-\beta^2) = x^2 - \dfrac{b^2-2ac}{a^2}x + \dfrac{c^2}{a^2}

and to make things look cleaner, scale the whole expression by a^2 to get

\boxed{a^2x^2 + (2ac-b^2)x + c^2}

4 0
3 years ago
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