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4 years ago

(9,-9)

Mathematics

2 answers:

uysha [10]4 years ago

8 0

Answer:

Step-by-step explanation:

erik [133]4 years ago

5 0

Answer:

Step-by-step explanation:

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What shapes has parallel sides only

olga2289 [7]

Square, Rectangle and Rhombus

5 0

3 years ago

What is the value of x in x+y=-10 and x-y=2

loris [4]

Answer:

x = -4

Step-by-step explanation:

x+y = -10 -------- (1)

x-y = 2 ------- (2)

from (1)

x+y = -10

y = -10-x -------- (3)

substitute (3) into (2)

x-y = 2

x-(-10-x) = 2

x+10+x = 2

2x = 2-10

2x = -8

x = -8/2

x = -4

6 0

3 years ago

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Your are part of a team studying an endangered species of land snail in upstate New York. You and your colleagues capture and ma

ELEN [110]

Answer:

720 individuals

Step-by-step explanation:

According to my research, I can say that based on the information provided within the question you can conclude that the population of land snails has about 720 individuals. We can calculate this by using the Rule of Three formula that is attached below.

x ⇒ 80 marked

45 ⇒ 5 marked

$\frac{45*80}{5} = x$

$720= x$

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0

3 years ago

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The greatest common factor using prime factorization for 28 and 63

Degger [83]

The answer is seven im sure

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4 years ago

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please solve it please solve it please solve it please solve it please solve it please solve it please solve it please solve it

katovenus [111]

Since $\alpha$ and $\beta$ are roots of $ax^2+bx+c$ , we can factorize the quadratic in terms of the roots as

$ax^2+bx+c = a(x-\alpha)(x-\beta)$

Expanding the right side gives

$ax^2+bx+c = ax^2-a(\alpha+\beta)x+a\alpha\beta$

so that

$\alpha + \beta = -\dfrac ba \\\\ \alpha\beta = \dfrac ca$

A polynomial with roots $\alpha^2$ and $\beta^2$ would be

$(x-\alpha^2)(x-\beta^2)$

and expanding this gives

$x^2 - (\alpha^2+\beta^2)x+\alpha^2\beta^2$

Now,

$\alpha\beta = \dfrac ca \implies \alpha^2\beta^2 = (\alpha\beta)^2 = \dfrac{c^2}{a^2}$

and

$(\alpha+\beta)^2 = \alpha^2 + 2\alpha\beta + \beta^2 \\\\ \implies \alpha^2+\beta^2 = \left(-\dfrac ba\right)^2 -2\left(\dfrac ca\right) = \dfrac{b^2-2ac}{a^2}$

So we can write the second quadratic in terms of $a,b,c$ as

$(x-\alpha^2)(x-\beta^2) = x^2 - \dfrac{b^2-2ac}{a^2}x + \dfrac{c^2}{a^2}$

and to make things look cleaner, scale the whole expression by $a^2$ to get

$\boxed{a^2x^2 + (2ac-b^2)x + c^2}$

4 0

3 years ago