105/495
I think that is the answer
To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can cancel out the -16t^2's to get
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Using this time value, plug into either equation to find the height.
h = 16(2.48)^2 + 56(2.48)
Final answer:
h = 40.4736
Hope I helped :)
Given:
The quadratic equation is:

To find:
The solution for the given equation rounded to 2 decimal places.
Solution:
Quadratic formula: If a quadratic equation is
, then:

We have,

Here,
. Using the quadratic formula, we get




Now,



And



Therefore, the required solutions are 1.14 and -1.47.
Answer:
B) The sample size was 100
Step-by-step explanation:
Number of sample size in January = 100
Number of sample size in March = 100
Number of sample size in June = 100
Number of sample size in September = 100
The average sample size for the study = (100 +100+100+100)/4
= 400/4
= 100
So the average sample size for the study is 100 women between 18 to 21 years.