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irina1246 [14]
2 years ago
9

X ⋅ x ⋅ x ⋅ x ⋅ x = ? 5x x(x + 5) x + 5 x5

Mathematics
2 answers:
vampirchik [111]2 years ago
6 0

Answer

x.x.x.x.x = 5x

Step-by-step explanation:

valina [46]2 years ago
6 0

Answer:

(

−

∞

,

∞

)

this is a link for help

Step-by-step explanation:

Simplify  

5

(

5

x

−

5

)

.

Tap for fewer steps...

Apply the distributive property.

5

(

5

x

)

+

5

⋅

−

5

=

25

(

x

−

1

)

Multiply.

Tap for more steps...

25

x

−

25

=

25

(

x

−

1

)

Simplify  

25

(

x

−

1

)

.

Tap for fewer steps...

Apply the distributive property.

25

x

−

25

=

25

x

+

25

⋅

−

1

Multiply  

25

by  

−

1

.

25

x

−

25

=

25

x

−

25

Move all terms containing  

x

to the left side of the equation.

Tap for fewer steps...

Subtract  

25

x

from both sides of the equation.

25

x

−

25

−

25

x

=

−

25

Combine the opposite terms in  

25

x

−

25

−

25

x

.

Tap for fewer steps...

Subtract  

25

x

from  

25

x

.

0

−

25

=

−

25

Subtract  

25

from  

0

.

−

25

=

−

25

Since  

−

25

=

−

25

, the equation will always be true for any value of  

x

.

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

(

−

∞

,

∞

)

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Neporo4naja [7]

Answer:

2.

sinα=√3/(2√7)

cosα=5/(2√7)

tanα=5/√3

cscα=(2√7)/√3

secα=(2√7)/5

*note* you can simplify the above further (by rationalizing them), but I think it's probably fine to leave them as is *

3.) g15.9

4.)25.4

5.) 70.8

6.) 36.4

Step-by-step explanation:

Cot is the inverse of toa so cot= adj/opp

This means the traingle's adjacent side is √3 and its opposite is 5

with this information let's figure out the hypotonouse

√3²+5²=c²

3+25=c²

28=c²

√28=c

√28=2√7

which means the triangle's

opposite= √3

hypotonous= 2√7

Adjacent= 5

With all of this we can just plug in the numbers to find the missing information (where α=angle or theta)

sinα=√3/(2√7)

cosα=5/(2√7)

tanα=5/√3

cscα=(2√7)/√3

secα=(2√7)/5

For this one we have the adjacent and need the opposite

we will use TOA

Tan(25)=x/34

34tan(25)=x

x=15.9

4.) For this one we have the adjacent but need the hypotonouse

we will use CAH

cos(48)=17/x

17/cos(48)=x

x=25.4

5.) for number 5 we have the oppsite and hypotonouse and so we'll use SOH

sin(α)=17/18

α=70.8

6.) For this one we have the opposite and adjacent and so we'll use TOA

Tan(α)=(31/42)

α=36.4

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Step-by-step explanation:

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1

Step-by-step explanation:

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