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irina1246 [14]
2 years ago
9

X ⋅ x ⋅ x ⋅ x ⋅ x = ? 5x x(x + 5) x + 5 x5

Mathematics
2 answers:
vampirchik [111]2 years ago
6 0

Answer

x.x.x.x.x = 5x

Step-by-step explanation:

valina [46]2 years ago
6 0

Answer:

(

−

∞

,

∞

)

this is a link for help

Step-by-step explanation:

Simplify  

5

(

5

x

−

5

)

.

Tap for fewer steps...

Apply the distributive property.

5

(

5

x

)

+

5

⋅

−

5

=

25

(

x

−

1

)

Multiply.

Tap for more steps...

25

x

−

25

=

25

(

x

−

1

)

Simplify  

25

(

x

−

1

)

.

Tap for fewer steps...

Apply the distributive property.

25

x

−

25

=

25

x

+

25

⋅

−

1

Multiply  

25

by  

−

1

.

25

x

−

25

=

25

x

−

25

Move all terms containing  

x

to the left side of the equation.

Tap for fewer steps...

Subtract  

25

x

from both sides of the equation.

25

x

−

25

−

25

x

=

−

25

Combine the opposite terms in  

25

x

−

25

−

25

x

.

Tap for fewer steps...

Subtract  

25

x

from  

25

x

.

0

−

25

=

−

25

Subtract  

25

from  

0

.

−

25

=

−

25

Since  

−

25

=

−

25

, the equation will always be true for any value of  

x

.

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

(

−

∞

,

∞

)

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Answer:

Step-by-step explanation:

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4 0
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Assume the hold time of callers to a cable company is normally distributed with a mean of 5.5 minutes and a standard deviation o
Ierofanga [76]

Answer:

The percent of callers are 37.21 who are on hold.

Step-by-step explanation:

Given:

A normally distributed data.

Mean of the data, \mu = 5.5 mins

Standard deviation, \sigma = 0.4 mins

We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.

Lets find z-score on each raw score.

⇒ z_1=\frac{x_1-\mu}{\sigma}   ...raw score,x_1 = 5.4

⇒ Plugging the values.

⇒ z_1=\frac{5.4-5.5}{0.4}

⇒ z_1=-0.25  

For raw score 5.5 the z score is.

⇒ z_2=\frac{5.8-5.5}{0.4}  

⇒ z_2=0.75

Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.

We have to work with P(5.4<z<5.8).

⇒ P(5.4

⇒ P(-0.25

⇒ P(z

⇒ z(1.5)=0.7734 and z(-0.25)=0.4013.<em>..from z -score table.</em>

⇒ 0.7734-0.4013

⇒ 0.3721

To find the percentage we have to multiply with 100.

⇒ 0.3721\times 100

⇒ 37.21 %

The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21

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