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2 years ago

Evaluate 5(x - 1) - 2 when x = 3

Mathematics

1 answer:

Elan Coil [88]2 years ago

4 0

Answer:

Step-by-step explanation:

Given algebraic expression:

5(x - 1) - 2

To:

Evaluate this expression using x = 3

Solution:

5(x - 1) - 2

Evaluate by plugging x = 3 to this expression:

5(3-1)-2

Simplify using PEMDAS.

5(2)-2
10-2
8

We can conclude:

By evaluating x = 3 to the given expression,the answer will be 8.

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What is the sum of the 14th square number and the 6th square number?

son4ous [18]

14th square number = 196

6th square number = 36

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3 years ago

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Answer:

for Question 2 its 2/7

Step-by-step explanation:

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3 years ago

Shkiper50 [21]

Answer:

The sweaters cost $35 each.

Step-by-step explanation:

The skirt was $20, so you would subtract 20 from 160. that equals 140. Then you would divide 140 by 4. that would equal 35. So the answer is $35.

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3 years ago

The measure of arc BCD is

makkiz [27]

Answer:

m∠BCD = 140°

Step-by-step explanation:

ABCD is cyclic quadrilateral. A property of cyclic quadrilateral states that the opposite angles of it sum up to 180°. Here:

m∠A + m∠C =180° and m∠B + m∠D = 180°

So, m∠A + m∠C =180°

m∠A = 40° (given in the question)

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6 0

3 years ago

Niles and Bob sailed at the same time for the same length of time. Niles' sailboat traveled 36 miles at a speed of 6 mph, while

kykrilka [37]

Answer:

Niles and Bob were traveling for 6 hours.

Step-by-step explanation:

The speed or rate at which an object is moving can be computed using the formula:

$s=\frac{d}{t}$

Here:

s = speed

d = distance traveled

t = time taken

It is provided that Niles and Bob sailed at the same time for the same length of time.

Speed of Niles sailboat is, s₁ = 6 mph.

Distance traveled by Niles' sailboat is, d₁ = 36 miles.

Speed of Bob's sailboat is, s₂ = 16 mph.

Distance traveled by Bob's sailboat is, d₂ = 96 miles.

It took both Niles and Bob the same time to travel the respective distance.

Compute the time it took Niles to travel 36 miles at 6 mph speed as follows:

$t_{1}=\frac{d_{1}}{s_{1}}$

$=\frac{36}{6}\\=6$

It took Niles 6 hours to travel 36 miles at 6 mph speed.

Compute the time it took Bob to travel 96 miles at 16 mph speed as follows:

$t_{2}=\frac{d_{2}}{s_{2}}$

$=\frac{96}{16}\\=6$

It took Bob 6 hours to travel 96 miles at 16 mph speed.

Thus, Niles and Bob were traveling for 6 hours.

7 0

4 years ago