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1 year ago

Evaluate 5(x - 1) - 2 when x = 3

Mathematics

1 answer:

Elan Coil [88]1 year ago

4 0

Answer:

Step-by-step explanation:

Given algebraic expression:

5(x - 1) - 2

To:

Evaluate this expression using x = 3

Solution:

5(x - 1) - 2

Evaluate by plugging x = 3 to this expression:

5(3-1)-2

Simplify using PEMDAS.

5(2)-2
10-2
8

We can conclude:

By evaluating x = 3 to the given expression,the answer will be 8.

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What does d equal in -24 + 12 (d - 3) + 22

zubka84 [21]

Answer:

-24+12(d-3)+22=-24+34(d-3)

10(d-3)

10d=-30

d=-30/10

d=3

4 0

3 years ago

Please help I need work shown!!

likoan [24]

3x-11=2x+11

x=22

3x-11=55

2x+11=55

55+55+2y=180

2y=70

y=35

x=22 , y=35

7 0

2 years ago

Read 2 more answers

Morgan has an investment worth $177,500. If his original investment was $50,000 and he received a 15% interest rate, how many ye

Illusion [34]

<h3>Morgan invested for 17 years</h3>

Solution:

From given,

Principal = $ 50, 000

Total amount = $ 177, 500

Rate of interest = 15 %

Number of years = ?

Interest amount = Total amount - principal

Interest amount = 177, 500 - 50, 000

Interest amount = 127500

Use the formula,

$Interest = \frac{p \times n \times r}{100}\\\\127500 = \frac{ 50000 \times n \times 15}{100}\\\\127500 = 500 \times 15 \times n\\\\75n = 1275\\\\n = 17$

Thus he invested for 17 years

8 0

2 years ago

Estimate the time it takes for a free fall drop from 10 meters height. Also estimate the time a 10 m platform diver would be in

murzikaleks [220]

Answer:

a) $t = \sqrt{\frac{2 *10m}{9.8 m/s^2}}=1.43s$

b) $4.9t^2 -2t -10 =0$

And we can use the quadratic formula to solve it:

$t = \frac{2 \pm \sqrt{(-2)^2 -4(4.9)(-10)}}{2*4.9}$

$t =\frac{2 \pm \sqrt{200}}{9.8}$

$t_1 =1.65 s, t_2 =-1.24 s$

And since the time can't be negative the correct option would be $t=1.65 s$

Step-by-step explanation:

For this case we can use the following kinematics formulas:

$y_f = y_o + V_o t + \frac{1}{2} a t^2$

For this case we assume that the only acceleration is the gravity a = g =9.8 m/s^2. And for this case we can assume that the reference point is $y_o =0$ and the final height would be $y_f = -10 m$ since is below the initial point.

Teh acceleration would be a=-g, since the gravity is acting dowward, we assume that the initial velocity is 0, so then we have everything to replace and we got:

$-10 m = 0m + (0m/s)t -\frac{1}{2} (9.8 m/s^2) t^2$