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Mandarinka [93]
2 years ago
7

1 Zx and Zy are supplementary angles. Zy measures 65º. What is the measure of Zx?​

Mathematics
2 answers:
Trava [24]2 years ago
7 0

Answer:

115°

Step-by-step explanation:

Given

Zy = 65°

Zx = ?

we know

Zx + Zy = 180° { being supplementary angles }

Zx + 65° = 180°

Zx = 180° - 65°

Zx = 115°

Hope it will help :)❤

Hitman42 [59]2 years ago
6 0

Answer:

zx=115'

Step-by-step explanation:

supplementary angles add up to 180'

180-65=115

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Point W has coordinates (4, -7). If it is translated left 4 units, what are the coordinates of its image?
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Answer:

(0, - 7)

Step-by-step explanation:

A translation of 4 units left means subtracting 4 from the original x- coordinate, but the y-coordinate remains unchanged

W(4, - 7 ) → W'(4 - 4, - 7 ) → W'(0, - 7 )


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2 years ago
What does 70.2 rounded to the nearest ten?
a_sh-v [17]

Answer:

70

Step-by-step explanation:

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Write three different equations that have x=5 as a solution
svlad2 [7]

Answer: The three different equations will be

x+3=8\\\\2x-8=2\\\\4x-4=16

Step-by-step explanation:

We have to write three equation that have x = 5 as a solution:

1) First equation will be

x+3=8\\\\x=8-3\\\\x=5

2) Second equation will be

2x-8=2\\\\2x=8+2\\\\2x=10\\\\x=\frac{10}{2}\\\\x=5

3) Third equation will be

4x-4=16\\\\4x=16+4\\\\4x=20\\\\x=\frac{20}{4}\\\\x=5

Hence, the three different equations will be

x+3=8\\\\2x-8=2\\\\4x-4=16



7 0
3 years ago
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(1 point) Linear System - Three Variables Solve the following system of equations using Gaussian elimination method. If there ar
EastWind [94]

Answer:

x=\frac{-363}{70} ≈ -5.1857

y=\frac{-192}{35} ≈ -5.4857

z=\frac{313}{84} ≈ 3.7262

Step-by-step explanation:

Rewrite the equation system as:

6x+8y=-75

-3x+6y+6z=5

2x-9y=39

Now, write the system in its augmented matrix form:

\left[\begin{array}{cccc}6&8&0&-75\\-3&6&6&5\\2&-9&0&39\end{array}\right]

applying row reduction process to  its associated augmented matrix:

Swap R1 and R3, and then Swap R1 and R2:

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\6&8&0&-75\end{array}\right]

R3+2R1

\left[\begin{array}{cccc}-3&6&6&5\\2&-9&0&39\\0&20&12&-65\end{array}\right]

3R2+2R1

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&20&12&-65\end{array}\right]

15R3+20R2

\left[\begin{array}{cccc}-3&6&6&5\\0&-15&12&127\\0&0&420&1565\end{array}\right]

Now we have a simplified system:

-3x+6y+6z=5\\0-15y+12z=127\\0+0+420z=1565

-3x+6y+6z=5\hspace{5 mm}(1)\\0-15y+12z=127\hspace{3 mm}(2)\\0+0+420z=1565\hspace{3 mm}(3)

From (3):

z=\frac{313}{84} (4)

Replacing (4) in (2)

y=\frac{-192}{35} (5)

Finally replacing (5) and (4) in (1)

x=\frac{-363}{70}

7 0
3 years ago
Which type of arc lies outside of the central angle and measures more than 180
Temka [501]
The answer is a major arc.
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