Question

What is the solution to the following system?

Answer 1

The solutions are x = 1, y = -3, z = 1 after solving with substitution method option second x= 1, y=-3, z = 1 is correct.

What is a linear equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have three linear equations in three variable:

4x + 3y - z = -6 ..(1)

6x - y+ 3z = 12 ..(2)

8x + 2y + 4z = 6 ...(3)

From the equation (1)

$\rm x=\dfrac{-6-3y+z}{4}$

Substitute the above value in the equation (2) and (3):

$\rm 6\cdot \dfrac{-6-3y+z}{4}-y+3z=12\\\\ 8\cdot \dfrac{-6-3y+z}{4}+2y+4z=6$

After simplification:

$\rm -11y+9z-18=24\\ -4y+6z-12=6$

After solving the above two equations by substitution method:

z = 1

y = -3

Plug the above two values in the equation (1), we get:

x = 1

Thus, the solutions are x = 1, y = -3, z = 1 after solving with substitution method option second x= 1, y=-3, z = 1 is correct.

Learn more about the linear equation here:

brainly.com/question/11897796

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