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-BARSIC- [3]
2 years ago
13

Angle A= 6x+18 degree

Mathematics
1 answer:
Oksanka [162]2 years ago
4 0

Answer: Hello and welcome to brainly, The answer for this question is Angle A = B

A = 6x + 18

B =  x + 93

A = B

Solve for x

6x + 18 = x + 93

6x - x = 93 -18

5x = 75

5x/5 = 75/5

x = 15

x = 15

Insert 15 into our equations.

6(x)+ 18  = ?

6(15)+ 18  = 108

x + 93 = ?

15 + 93 = 108

Answer = 108

Step-by-step explanation:

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The sum of two numbers is 12. The difference of the same two numbers is −4. Find the two numbers.
Butoxors [25]

Answer:

  4 and 8

Step-by-step explanation:

Let 'a' represent one of the numbers. Then the other is 12-a, and their difference is ...

  a - (12-a) = -4

  2a = 8 . . . . add 12

  a = 4 . . . . . divide by 2

  12-a = 8 . . . . find the other number

The two numbers are 4 and 8.

7 0
3 years ago
Read 2 more answers
Sam solved the following problem:
Talja [164]

Answer:

 Sam made it -24 versus 24  (29-5=24  not -24)

(Sam failed to flip the inequality)

Step-by-step explanation:

-4x + 5 > 29

Subtract 5 from each side

-4x+5-5 > 29-5

-4x > 24      Sam made it -24 versus 24  (29-5=24  not -24)

Divide by -4  Remember to flip the inequality

-4x/-4 < 24/-4   (Sam failed to flip the inequality)

x < -6

7 0
3 years ago
Read 2 more answers
Determine the solution to f(x) = g(x) using the following system of equations: (5 points) f(x) = 3x − 23 g(x) = −4.5x + 7
jeka94

Answer:

(The solution is (4, -11).

Step-by-stp explanation:

Let f(x) = g(x) = y:

y = 3x − 23

y = -4.5x + 7     Subtract the second equation from the first to eliminate y:

0 = 7.5x - 30

7.5x = 30

x = 4

Plug this into the first equation:

y = 3(4) - 23

y =  -11.

5 0
3 years ago
A juice shop needed 360 oranges to make 40 L of fresh squeezed juice how many oranges will be needed to make 60 L of fresh squee
marishachu [46]

Answer:

540 oranges

Step-by-step explanation:

360 Oranges=40L

40*3/2=60

360*3/2=540

5 0
3 years ago
Read 2 more answers
Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th
grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

S = \{1,1,2,2,2,3\}

And the probability of each is:

P(1) = \frac{n(1)}{n(s)}

P(1) = \frac{2}{6}

P(1) = \frac{1}{3}

P(2) = \frac{n(2)}{n(s)}

P(2) = \frac{3}{6}

P(2) = \frac{1}{2}

P(3) = \frac{n(3)}{n(s)}

P(3) = \frac{1}{6}

P(Odd Number) is then calculated as:

P(Odd\ Number) =  P(1) + P(3)

P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}

Take LCM

P(Odd\ Number) = \frac{2+1}{6}

P(Odd\ Number) = \frac{3}{6}

P(Odd\ Number) =  \frac{1}{2}

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

S = \{1,1,2,2,2,3,3\}

The probability of each is:

P(1) = \frac{n(1)}{n(s)}

P(1) = \frac{2}{7}

P(2) = \frac{n(2)}{n(s)}

P(2) = \frac{3}{7}

P(3) = \frac{n(3)}{n(s)}

P(3) = \frac{1}{7}

P(Odd\ Number) = P(1) + P(3)

P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}

Take LCM

P(Odd\ Number) = \frac{2+1}{7}

P(Odd\ Number) = \frac{3}{7}

Comparing P(Odd Number) before and after

P(Odd\ Number) =  \frac{1}{2} --- Before

P(Odd\ Number) = \frac{3}{7} --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0
3 years ago
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