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3 years ago

Which of the following is the most accurate definition of a function

Mathematics

1 answer:

kirill [66]3 years ago

7 0

a relationship or expression involving one or more variables

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Use grouping symbols and at least one exponent to write a numerical expression that has a value of 80.

Kaylis [27]

To group an expression, means that the factors of the expression are to be separated in (), [] or {}.

An expression with a value of 80 is: $2^2 \times ( [2 + 2] \times [3 + 2] )$

The number is given as:

$80$

Factorize

$80 = 2 \times 40$

Factorize 40

$80 = 2 \times 2 \times 20$

Express $2 \times 2$ as an exponent

$80 = 2^2 \times 20$

Express 20 as 4 x 5

$80 = 2^2 \times ( 4 \times 5)$

Express 5 as 3 + 2

$80 = 2^2 \times ( 4 \times [3 + 2] )$

Express 4 as 2 + 2

$80 = 2^2 \times ( [2 + 2] \times [3 + 2] )$

Hence, the above expression has a numerical value of 80

Read more about numerical expressions at:

brainly.com/question/24787226

6 0

2 years ago

What sentence about markdowns and markups is true?

Eduardwww [97]

The answer is C.
C. A markup has no limit, but a markdown is limited to 100% or less.

8 0

3 years ago

A landscaper waters a lawn during the summer.

svet-max [94.6K]

Answer:

Step-by-step explanation:

D bc yes

7 0

3 years ago

For which operations is the set {0, 1} closed?

velikii [3]

0 × 0 = 0
0 × 1 = 0
1 × 1 = 1

Which means multiplication is closed under {0, 1}

1 ÷ 1 = 1
0 ÷ 1 = 0

Division is not closed under {0, 1}

1 + 1 = 2

Addition is not closed under {0, 1}

0 - 1 = -1

Subtraction is not closed under {0, 1} either

So it's only A. Multiplication which is closed under {0, 1}

5 0

4 years ago

The half-life of Radium-226 is 1590 years. If a sample contains 200 mg, how many mg will remain after 1000 years?

adell [148]

Answer: 129.33 g

Step-by-step explanation:

$$$Let $p=A \cdot e^{n t}$ \\$(p=$ present amount, $A=$ initial amount, $n=$ decay rate, $t=$ time)$

$\begin{aligned}&\Rightarrow \text { Given } p=\frac{A}{2} \ a t \ t=1590 \\&\Rightarrow \frac{1}{2}=e^{1590n} \Rightarrow n=\frac{\ln (1 / 2)}{1590}=-0.00043594162\end{aligned}$

$If $A=200 \mathrm{mg}$ and $t=1000$ then,$$\begin{aligned}P &=200 e^{\left(\frac{\ln \left(1/2\right)}{1590}\right) \cdot 1000} \text \\\\&=129.33 \text { grams}\end{aligned}$

3 0

2 years ago