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babymother [125]
2 years ago
8

Hello. I need help on this question. Please answer if you know. Provide the answer with working. Thanks.

Mathematics
2 answers:
pishuonlain [190]2 years ago
6 0

Answer:

answers of the question

11Alexandr11 [23.1K]2 years ago
4 0

Answer:

a) - 11x - 94y / 12    b)  x -4 / 5- 3x   c) 12x - 11 /10y

Step-by-step explanation:

a)  2x - 6y / 4    -  4y - x/ 12    -   4x - 20y /3

6x - 18y / 12 -     4y - x / 12              -  16x - 80y / 12

= 5x - 14y / 12     - 16x - 80y / 12

- 11x - 94y / 12

b) x /5 -    4/ 3x =  x -4 / 5- 3x

c) 2x -3/ 5y  -    5- 2x / 10y + x/y

4x - 6 /10y   -  5-2x/ 10y +  10x / 10y

2x - 11 / 10  + 10x / 10y

= 12x - 11 /10y

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Suppose that y varies directly with x and y=12 when x=-2. What is x when y=-6 <br> Please help me!!
goldenfox [79]

9514 1404 393

Answer:

  x = 1

Step-by-step explanation:

You can work this several ways.

1) Consider the factor that gets you from the y-value of the known pair to the y-value of the unknown pair. Here, that factor is -6/12 = -1/2.

Then the unknown value of x is the known value multiplied by that same factor:

  x = (-1/2)(-2)

  x = 1

__

2) You can write the equation for a "varies directly" relationship and solve for the constant of proportionality. Then you can use that equation to find the unknown value of x.

  y = kx . . . . . . . . . . . . . . y varies directly with x

  k = y/x = 12/-2 = -6

Now we know ...

  y = -6x

Filling in the new value for y, we have ...

  -6 = -6x

  1 = x . . . . . . divide by -6

__

3) You can write a proportion. Since we want to find a value for x, it is convenient to put that in the numerator.

  -2/12 = x/-6

Multiplying by -6, we get ...

  (-6)(-2)/12 = x = 1

3 0
3 years ago
Find the volume of the figure please.
kow [346]

Answer:

1568 in^3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
For which is 3 NOT an element of the range?
Brilliant_brown [7]
Is your D y= - (- x) ^2
If so y would equal a negative so it cannot be 3
5 0
3 years ago
How do you do this question?
mr_godi [17]

Answer:

None of the above

Step-by-step explanation:

According to the divergence test, if the limit of a sequence as n approaches infinity does not equal 0, then the series diverges.  (Notice that if the limit does equal 0, the series doesn't necessarily converge).

According to the geometric series test, a geometric series converges if -1 < r < 1, and diverges otherwise.

The first series is a geometric series with r = -5/3.  So it diverges.

The second series is also a geometric series:

3ⁿ⁻¹ / 2ⁿ = ⅓ (3ⁿ / 2ⁿ) = ⅓ (3/2)ⁿ

r = 3/2, so it diverges.

For the third series, the limit as n approaches infinity equals 1.  This fails the divergence test, so this series also diverges.

For the fourth series, the limit as n approaches infinity equals 1.  This fails the divergence test, so this series also diverges.

5 0
3 years ago
Quadratic Data
EastWind [94]
I think it’s quadratic
7 0
3 years ago
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