The perimeter of the rectangle is 56 cm. Find the value of x. 10 cm 3x cm
2 answers:
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Answer:
See explanation
Step-by-step explanation:
Jacob has 75 cookies.
He gave 2 cookies to each student.
Complete the table:
Let n be the number of students. After nth student arrived Jacob had left
cookies.
This is an arithmetic sequence with
Thus,
Answer:
See the proof below.
Step-by-step explanation:
What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where . If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"
Proof
Since we have a if and only if w need to proof the statement on the two possible ways.
If X is linearly dependent, then a vector is a linear combination
We suppose the set is linearly dependent, so then by definition we have scalars
in C such that:
And not all the scalars are equal to 0.
Since at least one constant is non zero we can assume for example that , and we have this:
We can divide by c1 since we assume that and we have this:
And as we can see the vector can be written a a linear combination of the remaining vectors
. We select v1 but we can select any vector and we get the same result.
If a vector is a linear combination, then X is linearly dependent
We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select and we have this:
For scalars defined in C. So then we have this:
So then we can conclude that the set X is linearly dependent.
And that complet the proof for this case.
Answer:
.
Step-by-step explanation:
How many unique combinations are possible in total?
This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination
.
How many out of that 2,118,760 combinations will satisfy the request?
Number of ways to choose 2 red candies out a batch of 28:
.
Number of ways to choose 3 green candies out of a batch of 8:
.
However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing
.
The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:
.