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Sloan [31]
3 years ago
12

The perimeter of the rectangle is 56 cm. Find the value of x. 10 cm 3x cm

Mathematics
2 answers:
krek1111 [17]3 years ago
7 0
Answer: x = 6

Explanation:

P = 2(l + w)
56 = 2(3x + 10)
56 = 6x + 20
56 - 20 = 6x
36 = 6x
36/6 = x
6 = x

Therefore, x = 6
andriy [413]3 years ago
4 0
56-10=46. 46 divided by 3=15.3 with the 3 repeating
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A road bike has a wheel diameter of 622 mm. What is the circumference of the wheel? Use 3.14 for pi
Ghella [55]

Answer:

Circumference ≅ 195 mm

Step-by-step explanation:

The circumference of a circle is equal to: 2*\pi *radius

Since Diameter = 2*radius we can replace that in the circumference equation giving us:

Circumference = \pi *Diameter

We know Diameter = 622 mm and pi = 3.14 so:

Circumference = \pi *Diameter = 3.14 * 622 mm = 195.308 mm

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3 years ago
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Find the major intercepts for the ellipse shown below.<br> A. (0, ±3)<br> B. (±3, 0)<br> C. (±2, 0)
Serggg [28]

Answer:

A(0,+3)

Step-by-step explanation:

Hopefully this helps

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3 years ago
Can someone show me an equation and solves this problem for me Please?!
Vinvika [58]
The coach can buy 16 uniforms with $4.50 left.

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3 years ago
What is the area of the playGround show below 20 feet and 5 feet
Vikentia [17]
100 because 20*5=10p
5 0
3 years ago
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Use the Fundamental Theorem for Line Integrals to find Z C y cos(xy)dx + (x cos(xy) − zeyz)dy − yeyzdz, where C is the curve giv
Harrizon [31]

Answer:

The Line integral is π/2.

Step-by-step explanation:

We have to find a funtion f such that its gradient is (ycos(xy), x(cos(xy)-ze^(yz), -ye^(yz)). In other words:

f_x = ycos(xy)

f_y = xcos(xy) - ze^{yz}

f_z = -ye^{yz}

we can find the value of f using integration over each separate, variable. For example, if we integrate ycos(x,y) over the x variable (assuming y and z as constants), we should obtain any function like f plus a function h(y,z). We will use the substitution method. We call u(x) = xy. The derivate of u (in respect to x) is y, hence

\int{ycos(xy)} \, dx = \int cos(u) \, du = sen(u) + C = sen(xy) + C(y,z)  

(Remember that c is treated like a constant just for the x-variable).

This means that f(x,y,z) = sen(x,y)+C(y,z). The derivate of f respect to the y-variable is xcos(xy) + d/dy (C(y,z)) = xcos(x,y) - ye^{yz}. Then, the derivate of C respect to y is -ze^{yz}. To obtain C, we can integrate that expression over the y-variable using again the substitution method, this time calling u(y) = yz, and du = zdy.

\int {-ye^{yz}} \, dy = \int {-e^{u} \, dy} = -e^u +K = -e^{yz} + K(z)

Where, again, the constant of integration depends on Z.

As a result,

f(x,y,z) = cos(xy) - e^{yz} + K(z)

if we derivate f over z, we obtain

f_z(x,y,z) = -ye^{yz} + d/dz K(z)

That should be equal to -ye^(yz), hence the derivate of K(z) is 0 and, as a consecuence, K can be any constant. We can take K = 0. We obtain, therefore, that f(x,y,z) = cos(xy) - e^(yz)

The endpoints of the curve are r(0) = (0,0,1) and r(1) = (1,π/2,0). FOr the Fundamental Theorem for Line integrals, the integral of the gradient of f over C is f(c(1)) - f(c(0)) = f((0,0,1)) - f((1,π/2,0)) = (cos(0)-0e^(0))-(cos(π/2)-π/2e⁰) = 0-(-π/2) = π/2.

3 0
3 years ago
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