The measure of BD and BC are 7 and 7√2 respectively
A triangle is a shape with 3 sides and angles.
According to the theorem
CD/BD = BD/DA
From the given figure
CD = DA = 14/2
CD = DA = 7
Substitute
7/BD = BD/7
BD² = 7²
BD² = 49BD = 7
Determine the measure of BC
sin 45 = BD/BCsin45 = 7/BCBC = 7/sin45
BC = 7√2
Hence the measure of BD and BC are 7 and 7√2 respectively
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Answer:
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Step-by-step explanation:
k
c and b and a
9514 1404 393
(0.5, -2.5)
Each of the coordinates of B(1, -5) is multiplied by the scale factor, 0.5:
B' = (0.5·1, 0.5·(-5)) = (0.5, -2.5)
The coordinates of B' are (0.5, -2.5).
Rhombus