in 2010 an enormous sinkhole suddenly appeared in the middle of a guatemalan neighborhood and swallowed a three story building a
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We need to solve for the angles of the smaller triangle in order to solve for the angle of the larger triangle which would help us solve the missing measurement of a side.
Given:
51 degrees.
Cut the triangle into two equal sides and it forms a right triangle. All interior angles of a triangle sums up to 180 degrees.
180 – 51 – 90 = 39 degrees
39 degrees * 2 = 78 degrees.
Angle Q is 78 degrees.
In the bigger triangle, 4.3 is the hypotenuse. We need to solve for the measurement of the long leg which is the opposite of the 78 degree angle.
We will use the formula:
Sine theta = opposite / hypotenuse
Sin(78 deg) = opposite / 4.3
Sin(78 deg) * 4.3 = opposite
4.21 = opposite. This is also the height of the triangle.
Area of a triangle = ½ * base * height
A = ½ * 3units * 4.21units
A = 6.315 square units.
The smaller the angle subtended by a side, the smaller the length of the
side.
The correct responses are;
Question 1: The list of sides from shortest to longest are;
- MO/Shortest MO/Medium and MO/Longest
a) <u>Friday</u>
b) <u>70 minutes</u>
c) <u>40%</u>
d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>
From the given diagram, we have, the measure of the third angle, ∠O, is
found as follows;
∠O = 180° - 54° - 61° = 65°
Therefore, ∠O = The largest angle
We get;
The longest side is opposite the largest angle, which gives;
The shortest side is the side opposite ∠N (54°)=
The next shortest side is the side opposite ∠M(61°) =
The longest side is the side opposite ∠O(65°) =
a) The time spent training on Tuesday = 60 + 10 = 70 minutes
The time spent training on Thursday = 50 + 30 = 80 minutes
The time spent training on Friday = 45 + 40 = 85 minutes
Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>
b) The time spent training on Monday = 10 + 20 = 30 minutes
The time spent training on Wednesday = 20 + 15 = 35 minutes
Therefore, we get;
30, 35, 70, 80, and 85
The median total number of minutes the athlete spent training each day = <u>70 minutes</u>
<u />
c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120
The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300
=
×
%
d) The mean number of minutes spent on strength training is found as follows;
The mean number of minutes spent on aerobic training is found as follows;
The mean total number of minutes spent training, =
= 60
Therefore;
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