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Oksana_A [137]
2 years ago
14

Combine the radicals 4√7+3√28.

Mathematics
2 answers:
Ierofanga [76]2 years ago
8 0

Answer:

10√7    

Step-by-step explanation:

To combine the radicals, you must have the same number under both radicands. Luckily, you can simplify one of the radicands. This is done by separating the radicand (√28) into its common factors (√4 x √7) and taking the square root of one of the factors (√4 = 2).

4√7 + 3√28                                 <---- Original expression

4√7 + 3(√4 x √7)                         <---- Expand √28

4√7 + (3 x 2)√7                           <----- Take √4

4√7 + 6√7                                   <---- Multiply coefficients

10√7                                            <---- Add both terms

notka56 [123]2 years ago
6 0

Answer:

10√7

Step-by-step explanation:

4 \sqrt{7}  + 3 \times 2 \sqrt{7}  \\ 4 \sqrt{7}  + 6 \sqrt{7}  \\ 10 \sqrt{7}

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Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

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3 years ago
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Molodets [167]

Answer:

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Step-by-step explanation:

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G 3.6 Dice rolls. If you roll a pair of fair dice, what is the probability of (a) getting a sum of 1
Paladinen [302]

Answer:

0

Step-by-step explanation:

In the roll of a pair of fair dice, The sample space is as follows:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

If x,y represent  the  possible outcome of rolling the two die

Then the total number of possibilities for  the sample space = (x,y)

= (6 × 6) = 36

Now, the probability of getting a sum of 1 does not exist in the roll of a pair of  fair dice.

Therefore, Probability(1) = 0

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Answer:

first we should add both purchase price

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$20 - $14

=$6

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