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3 years ago

Hello, if you’re feeling generous today please lend a hand!! thank you

Mathematics

1 answer:

andrew11 [14]3 years ago

3 0

Answer:

$x \leqslant 2$

Step-by-step explanation:

The point is shaded which means its is equal to and since the arrow goes to the left it is less than. Therefore x is less than or equal to 2

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Which expression is equivalent to the given expression?

sdas [7]

The answer is C = 36n30

4 0

3 years ago

5 (- 3 x - 2) - (x - 3) = - 4 (4 x + 5) + 13

Montano1993 [528]

PEMDAS
parentheses, exponent, multiplication/division, addition/subtraction
first, start with what is inside the parentheses that is solvable.
5(6) - (x-3) = -4(4x+5) + 13
multiply what you can
30 - (x-3) = -16x - 20 + 13
simplify
30 - (x-3) = -16x - 7
subtract 30 on both sides
- (x-3) = -16x - 37
let’s separate -(x-3).
-x - 3 = -16x - 37
add 16x to both sides
15x - 3 = -37
add 3 to both sides
15x = -34
x = -34/15 or -2.2667

7 0

4 years ago

Read 2 more answers

The equation p(t) = 1.e represents a

zvonat [6]

Answer:

(b), (d) and (e)

Step-by-step explanation:

Given

$p(t) = 1 * e^t$

See attachment for $y = p(t)$

Required

Select true statements from the given options

(a) $\ln(30)$ = days the bacteria reaches 30000

We have:

$p(t) = 1 * e^t$

In this case:

$t = \ln(30)$ and $p(t) = 30000$

So, we have:

$30000 = 1 * e^{\ln(30)}$

$30000 = e^{\ln(30)}$

Using a calculator, we have:

$e^{\ln(30)} = 30$

So:

$30000 = 30$

The above equation is false.

(a) is not true

(b) The graph shows that $\ln(20) \approx 3$

We have:

$p(t) = 1 * e^t$

Let t = 3

So;

$p(3) = 1 * e^3$

From the graph, $p(3) = 20$

So:

$20 = 1 * e^3$

$20 = e^3$

Take natural logarithm of both sides

$\ln(20) = \ln(e^3)$

This gives:

$\ln(20) = 3$

(b) is true

(c) $\ln(t) = y$ is the logarithm form of $y = e^t$

We have:

$y = e^t$

Take natural logarithm of both sides

$\ln(y) = \ln(e^t)$

This gives:

$\ln(y) = t$

$\ln(y) = t$ $\ne$ $\ln(t) = y$

(c) is false

(d) $e^4 > 50$ and $\ln(50) < 4$

From the graph, we have:

$e^4 = 54$ --- rough readings

This implies that:

$e^4 > 50$ is true

Because $54 > 50$

Take natural logarithm of both sides

$\ln(54) > \ln(50)$

Rewrite as:

$\ln(50) < \ln(54)$

We have:

$e^4 = 54$

Take natural logarithm of both sides

$\ln(e^4) = \ln(54)$

$4 = \ln(54)$

$\ln(54) = 4$

Substitute $\ln(54) = 4$ in $\ln(50) < \ln(54)$

$\ln(50) < 4$

(d) is true

(e) The graph shows that $10 \approx \ln(2.3)$

We have:

$p(t) = 1 * e^t$

Let t = 2.3

So;

$p(2.3) = 1 * e^{2.3}$

From the graph,

$p(2.3) = 10$ ---- rough readings

So:

$10 = 1 * e^{2.3}$

$10 = e^{2.3}$

Take natural logarithm of both sides

$\ln(10) = \ln(e^{2.3})$

This gives:

$\ln(10) = 2.3$

(e) is true

4 0

3 years ago

Find the area of the shaded polygon

Mars2501 [29]

Answer:

372

Step-by-step explanation:

area of trapezium = a+b/2 * h

a is the length on top

b is the length on the bottom

h is the height

7+24/2*24=

=372

6 0

2 years ago

Find the GCF of the given polynomial.<br><br> 8x6y5 - 3x8y3

Whitepunk [10]

The GCF of this polynomial is x^6y^3.
8x^6y^5 - 3x^8y^3 = x^6y^3 (8y^2 - 3x^2)

This polynomial cannot be factorized any further. Hope this helps!

6 0

4 years ago

Read 2 more answers