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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Mathematics

1 answer:

Effectus [21]3 years ago

5 0

x^2 + 50

= (x + √50i)(x - √50i)

or you could write it as

(x + 5√2i)(x - √5√2i)

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Nadia is a stockbroker. She earns 12% commission each week. Last week, she sold $5400 worth of stocks. How much did she make las

Inga [223]

Answer:

a). Nadia made a total of $825 last week in commission sales

b). The total amount Nadia in commission in 2011=$42,900

Step-by-step explanation:

Step 1

Express the amount in commission she earns from her sales as follows;

C=S×r

where;

C=commission earned

S=total value of stock sales

r=commission rate

In our case;

C=unknown

S=$7,500

r=11%=11/100=0.11

replacing;

C=11% of 7,500

C=(11/100)×7,500

C=0.11×7,500=825

Nadia made a total of $825 last week in commission sales

b). To express the total amount she made in 2011, we derive the formula below;

Total amount (2011)=Average weekly commission×number of weeks in 2011

where;

Average weekly commission=$825

number of weeks in 2011=52

replacing;

Total amount (2011)=(825×52)=42,900

The total amount Nadia in commission in 2011=$42,900

6 0

3 years ago

PLEASE help, I'm begging, this was due to all the way back at November 12th, please help!!! Finding the Inverse of a Function Al

Nastasia [14]

Answer:

Step-by-step explanation:

6 0

2 years ago

Find the derivative of f(x) = 6/x at x = -2. select one: a. 6 b. 3/2 c. -3/2 d. -6

Ivenika [448]

F(X) = 6/X

F(X) = 6 • 1/X

F(X) = 6 • x^-1

F(X) = 6x^-1

F'(X) = 6 • d(x^-1)/dx

F'(X) = 6 • -1x^-1-1

F'(X) = 6 • -1x^-2

F'(X) = -6x^-2

F'(X) = -6/x^2
F'(-2) = -6/(-2)^2
F'(-2) = -6/4
F'(-2) = -3/2

The solution would be C. -3/2.

5 0

3 years ago

The radius of circle A is three feet less than twice the diameter of circle B. If the sun mmm of the diameters of both circles i

yanalaym [24]

Answer:

Area of Circle A = 1133.54

Circumference of Circle A= 119.32

Step-by-step explanation:

Given: Sum of both circle diameters= 49 feet.

Circle A radius= Three feet less than twice the diameter of circle B.

Lets assume diameter of Circle B is "x"

∴ Circle A radius (r)= $(2x-3)$

We know, the diameter of circle is $2r$

Diameter of Circle A is $2\times (2x-3)$

Next as given sum of both circle diameter is 49 feet.

∴ $2(2x-3)+x= 49\ feet$

distributing 2 with 2x and -3

⇒ $4x-6+x= 49$

⇒ $5x-6= 49$

Adding both side by 6

⇒ $5x=55$

Cross multiplying both side.

⇒ $x=\frac{55}{5} = 11$

∴ Diameter of circle B is 11 feet.

Next, subtituting the value of x to get the value of radius for Circle A.

Radius of circle A= $(2x-3)$

⇒ Radius of circle A= $(2\times 11-3)= 22-3$

∴ Radius of circle A= 19 feet.

Area of circle= $\pi r^{2}$

Taking π= 3.14

Area of circle A= $3.14\times 19^{2} = 3.14\times 361$

∴ Area of circle A= 1133.54

Circumference of circle= 2πr

Circumference of Circle A= $2\times 3.14\times 19= 119.32$

∴ Circumference of Circle A= 119.32

3 0

3 years ago

Read 2 more answers

A truck rental company rents a moving truck One Day by charging $39 + 0.09 per mile write a linear equation that relates the cos

Ivanshal [37]

Answer:

$(a)\ c(x) = 39 + 0.09 x$

$(b)\ \$53.4$

Step-by-step explanation:

Given

$Base\ Charge = \$39$

$Rate = 0.09$ per mile

Solving (a): Linear Equation

The total charges (c(x)) is: the base charge + the rate * number of miles (x).

So, we have:

$c(x)= 39 + 0.09 * x$

$c(x) = 39 + 0.09 x$

Solving (b): Cost of rent, if miles = 160

This implies that x = 160

So, we have:

$c(x) = 39 + 0.09 x$

$c(160) = 39 + 0.09 *160$

$c(160) = 39 + 14.4$

$c(160) = 53.4$

7 0

3 years ago