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Komok [63]
3 years ago
7

What is the value of x? x =

Mathematics
2 answers:
kirill [66]3 years ago
7 0

Answer:

the value is x=2

maw [93]3 years ago
5 0
Check the picture below.

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NEED HELP ASAP !!!<br><br> Simplify: √16r<br> O 47²<br> O 473<br> 87²<br> O 8-3
Vlad1618 [11]

Answer:

4 r^3

Step-by-step explanation:

sqrt ( 16 r^6 )    = sqrt ( 4^2 * (r^3)^2  )    =   4 r^3

6 0
1 year ago
LOTS OF POINTS!!!<br> SOLVE ANd EXPLAIN PROBLEM 8
alexandr1967 [171]

Answer:

r≈2.26in

Step-by-step explanation:

3 0
3 years ago
Can someone help please ? Thanks I’m advance
Pani-rosa [81]

Answer:

f(-3) = 16

Step-by-step explanation:

Given:

f(x) = 2x² + x + 1

Required:

f(-3)

Solution:

Substitute x = -3 into f(x) = 2x² + x + 1

f(-3) = 2(-3)² + (-3) + 1

f(-3) = 2*9 - 3 + 1

f(-3) = 18 - 3 + 1

f(-3) = 16

6 0
3 years ago
How many fluid ounces are in a bottle of soda that has 337 ml of fluid
VLD [36.1K]
11.3953 fluid ounces in 337 milliliters.

One milliliter is equal to 0.0388 fluid ounces.
5 0
1 year ago
A car braked with a constant deceleration of 16ft/s2, producing skid marks measuring 200 feet before coming to a stop. How fast
Llana [10]

Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.

Step-by-step explanation:

The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,

a = - 16ft/s^2

While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.

This means that it travelled a distance,

s = 200 feet

We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.

Since the car came to a stop, its final velocity, v = 0

Applying Newton's equation of motion,

v^2 = u^2 + 2as

0 = u^2 - 2 × 16 × 200

u^2 = 6400

u = √6400

u = 80 ft/s

7 0
3 years ago
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