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liq [111]
3 years ago
13

if x is a positive integer, which expression is equivalent to 4SqrRoot x^3 over 5SqrRoot x^2? Assume x > 0

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0

Answer:

The given expression  \frac{4\sqrt{x^3}}{5\sqrt{x^2} } is equivalent to \frac{4{\sqrt{x}}}{5}

Step-by-step explanation:

Given: if x is a positive integer then given expression \frac{4\sqrt{x^3}}{5\sqrt{x^2} }

We have to write an equivalent fraction to the given expression \frac{4\sqrt{x^3}}{5\sqrt{x^2} }

Consider the given expression \frac{4\sqrt{x^3}}{5\sqrt{x^2} }

Rewrite \sqrt{x^3}=\sqrt{x^2} \sqrt{x}

We get,

\frac{4\sqrt{x^2}{\sqrt{x}}}{5\sqrt{x^2}}

Canceling \sqrt{x^2} term, we get,

\frac{4{\sqrt{x}}}{5}

Thus, The given expression  \frac{4\sqrt{x^3}}{5\sqrt{x^2} } is equivalent to \frac{4{\sqrt{x}}}{5}

insens350 [35]3 years ago
3 0

Answer list is a) 20√7 b)x(20√x+3) c)6√x^5/x^2 d)x^3(6√x^5 I want some help with this as well

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Luba_88 [7]

Answer:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would earn a certificate of recognition from the fitness association

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the time for this event of a population, and for this case we know the distribution for X is given by:

X \sim N(470,60)  

Where \mu=470 and \sigma=60

NOTE: For this case the fastest 10% is on the lower tail of the distribution

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.9   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.1 of the area on the left and 0.9 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.1 and P(z>-1.28)=0.9

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-1.28

And if we solve for a we got

a=470 -1.28*60=393.2

So the value of height that separates the bottom 10% (Fastest 10%) of data from the top 90% is 393.2.

so if the time is 393.2 or lower a boy would  earn a certificate of recognition from the fitness association

4 0
3 years ago
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