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liq [111]
3 years ago
13

if x is a positive integer, which expression is equivalent to 4SqrRoot x^3 over 5SqrRoot x^2? Assume x > 0

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0

Answer:

The given expression  \frac{4\sqrt{x^3}}{5\sqrt{x^2} } is equivalent to \frac{4{\sqrt{x}}}{5}

Step-by-step explanation:

Given: if x is a positive integer then given expression \frac{4\sqrt{x^3}}{5\sqrt{x^2} }

We have to write an equivalent fraction to the given expression \frac{4\sqrt{x^3}}{5\sqrt{x^2} }

Consider the given expression \frac{4\sqrt{x^3}}{5\sqrt{x^2} }

Rewrite \sqrt{x^3}=\sqrt{x^2} \sqrt{x}

We get,

\frac{4\sqrt{x^2}{\sqrt{x}}}{5\sqrt{x^2}}

Canceling \sqrt{x^2} term, we get,

\frac{4{\sqrt{x}}}{5}

Thus, The given expression  \frac{4\sqrt{x^3}}{5\sqrt{x^2} } is equivalent to \frac{4{\sqrt{x}}}{5}

insens350 [35]3 years ago
3 0

Answer list is a) 20√7 b)x(20√x+3) c)6√x^5/x^2 d)x^3(6√x^5 I want some help with this as well

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Answer:

The product is the difference of squares is $$\left(xy-9\right)\left(xy+9\right)={{x}^2}{{y}^2}-81$$

Step-by-step explanation:

Explanation

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$$\begin{aligned}&(x y-9)(x y+9)=(x y)^{2}-(9)^{2} \\&(x y-9)(x y+9)=x^{2} y^{2}-81\end{aligned}$$

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Three consecutive even integers add to −6. What are these integers?
notka56 [123]
----------------------------------------------------
Define the numbers
----------------------------------------------------
Let the first even number be x
1st even number = x
2nd even number = x + 2
3rd even number = x + 4

----------------------------------------------------
Form the equation and solve
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3x = - 12
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----------------------------------------------------
Find the numbers
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1st even number = x = -4
2nd even number = x + 2 = -4 + 2 = -2
3rd even number = x + 4 = -4 + 4 = 0

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Answer:

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Step-by-step explanation:

I) Figure out how much grams of fat is in 1g of margarine:

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II) Next, we can figure out how much fat is in 82 g of margarine:

0.72 × 82 = 59.04

One shot formula:

(3.6g ÷ 5g) × 82g = 59.04g

8 0
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B

Step-by-step explanation:


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