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2 years ago

What equation is equivalent to the equation 9x - 13 = 4x + 32

Mathematics

1 answer:

Zigmanuir [339]2 years ago

8 0

I’m guessing if you simplify this it’s gonna be x=6

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3. <br> Point C(9,-6) is dilated using a scale factor<br> of 2/3. What are the coordinates of C"?

bonufazy [111]

Answer:3.08e

Step-by-step explanation:mujwjwieekedkd

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3 years ago

Read 2 more answers

Solve the following system of equations and show all work.<br> y = 2x^2 +9x<br> y = 4x + 25

Genrish500 [490]

Answer:

x = 5/2 thì y = 35 và x = -5 thì y = 5

Step-by-step explanation:

thay y = 4x + 25 vào phương trình y = 2x ^ 2 + 9x ta có:

4x + 25 = 2x ^ 2 + 9x

⇒2x ^ 2 + 5x - 25 = 0

⇒ x = 5/2 và x = -5

thay x = 5/2 vào phương trình y = 4x + 25 ⇒ y = 4*(5/2) + 25 = 35

thay x = -5 vào phương trình y = 4x + 25 ⇒ y = 4*(-5) + 25 = 5

7 0

3 years ago

PLS HELP DUE IN AN HOUR!

Flauer [41]

answer is attached with solution

answer is 5/17

8 0

2 years ago

PLEASE HELP ASAP!!!!!!!

umka2103 [35]

Answer:

dum there is part A prat B and C

Step-by-step explanation:

5 0

3 years ago

The following data were collected from 12 rain gauges in a park. Build a 95% CI for the mean rainfall at the park.

dybincka [34]

Answer:

Critical values: $t_{\alpha/2}=-2.201$ $t_{1-\alpha/2}=2.201$

95% confidence interval would be given by (3.646;4.472)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The data is:

4.65 3.89 2.73 4.35 3.80 4.86 4.33 4.37 4.76 4.05 3.05 3.87

2) Compute the sample mean and sample standard deviation.

In order to calculate the mean and the sample deviation we need to have on mind the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$

=AVERAGE(4.65,3.89,2.73, 4.35, 3.8, 4.86, 4.33, 4.37, 4.76, 4.05, 3.05, 3.87)

On this case the average is $\bar X= 4.059$

=STDEV.S(4.65,3.89,2.73, 4.35, 3.8, 4.86, 4.33, 4.37, 4.76, 4.05, 3.05, 3.87)

The sample standard deviation obtained was s=0.6503

3) Find the critical value t* Use the formula for a CI to find upper and lower endpoints

In order to find the critical value we need to take in count that our sample size n =12 <30 and on this case we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by: