Step-by-step explanation:
since the 2 arc angles cover the full circle, we know their sum must be 360°.
so,
23x - 5 + 37x + 5 = 360
60x = 360
x = 6
and so the angle at V = 5×6 + 17 = 30+17 = 47°
<span>5(x -5) = x(14 -4) =>5*x-5*5=x*10 => 5x-25=10x =>10x-5x=-25 =>5x=-25 => x= -25/5=-5</span>
Have a nice day!! ^^<span>
</span>
Answer:
2 solutions
Step-by-step explanation:
Set up a system of equations. The absolute value produces two equations because one answer will be negative and the other positive.
d + 4 = -9
d + 4 = 9
So...
d = -13
d = 5
Answer:
x=2ln(2)/(2ln(2)-ln(3))
Step-by-step explanation:
ln(4^x-1)=ln(3^x)
(x-1)ln(4)=ln(3^x)
(x-1)ln(4)=xln(3)
ln(4)x-ln(4)=xln(3)
ln(4)x=ln(3)x+2ln(2)
2ln(2)x-ln(3)x=2ln(2)
(2ln(2)-ln(3))x=2ln(2)
Therefore, x=2ln(2)/(2ln(2)-ln(3))
Answer:
3 tents hold 2 campers
Step-by-step explanation:
The given relations can be expressed as a single equation in the number of 2-camper tents.
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Let x represent the number of 2-camper tents. Then the number of 4-camper tents is 6-x, and the total number of campers in tents is ...
2x +4(6 -x) = 18
-2x +24 = 18
-2x = -6 . . . . . . subtract 24
x = 3 . . . . . . . divide by -2
Exactly 3 tents hold 2 campers.
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<em>Additional comment</em>
The other 3 tents hold 4 campers.
Another way to consider this is to assume that all tents hold 2 campers, and then realize there are 18 -6×2 = 6 campers left over. If these are placed 2 per tent, then there will be 6/2 = 3 tents with 4 campers. The remaining 3 tents will have 2 campers.
