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1 year ago

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Please help me find the volume

1 answer:

Iteru [2.4K]1 year ago

7 0

The formula for calculating the volume of a cube is expressed as V = L³. The volume of the cube is 1/27 cubic meters

<h3>How to find the volume of the cube?</h3>

The formula for calculating the volume of a cube is expressed as:

V = L³

where:

L = 1/3cm

Substitute

V = (1/3)³
V = 1/3³

V = 1/27 cubic meters

Hence the volume of the cube is 1/27 cubic meters

Learn more on volume of cube here: brainly.com/question/1972490

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PLEASE HELP ILL MARK BRAINLIEST !!!

Alexus [3.1K]

Answer:

a) the common difference is 20

b) $x_8=115 , x_{12}=195$

c) the common difference is -13

d) $a_{12}=52, a_{15}=13$

Step-by-step explanation:

a) what is the common difference of the sequence xn

Looking at the table, we get x_3=16, x_4=36 and x_5= 56

Deterring the common difference by subtracting x_4 from x_3 we get

36-16 =20

So, the common difference is 20

b) what is x_8? what is x_12

The formula used is: $x_n=x_1+(n-1)d$

We know common difference d= 20, we need to find $x_1$

Using $x_3=16$ we can find $x_1$

$x_n=x_1+(n-1)d\\x_3=x_1+(3-1)d\\15=x_1+2(20)\\15=x_1+40\\x_1=15-40\\x_1=-25$

So, We have $x_1 = -25$

Now finding $x_8$

$x_n=x_1+(n-1)d\\x_8=x_1+(8-1)d\\x_8=-25+7(20)\\x_8=-25+140\\x_8=115$

So, $\mathbf{x_8=115}$

Now finding $x_{12}$

$x_n=x_1+(n-1)d\\x_{12}=x_1+(12-1)d\\x_{12}=-25+11(20)\\x_{12}=-25+220\\x_{12}=195$

So, $\mathbf{x_{12}=195}$

c) what is the common difference of the sequence $a_m$

Looking at the table, we get a_7=104, a_8=91 and a_9= 78

Deterring the common difference by subtracting a_7 from a_8 we get

91-104 =-13

So, the common difference is -13

d) what is a_12? what is a_15?

The formula used is: $a_n=a_1+(n-1)d$

We know common difference d= -13, we need to find $a_1$

Using $a_7=104$ we can find $x_1$

$a_n=a_1+(n-1)d\\a_7=a_1+(7-1)d\\104=a_1+7(-13)\\104=a_1-91\\a_1=104+91\\a_1=195$

So, We have $a_1 = 195$

Now finding $a_{12}$ , put n=12

$a_n=a_1+(n-1)d\\a_{12}=a_1+(12-1)d\\a_{12}=195+11(-13)\\a_{12}=195-143\\a_{12}=52$

So, $\mathbf{a_{12}=52}$

Now finding $a_{15}$ , put n=15

$a_n=a_1+(n-1)d\\a_{15}=a_1+(15-1)d\\a_{15}=195+14(-13)\\a_{15}=195-182\\a_{15}=13$

So, $\mathbf{a_{15}=13}$

5 0

3 years ago

Convert 165 pounds into kilograms.

Elenna [48]

Answer: D. 74.91

One pound is 2.205 kilograms, so we can find how many kilograms are in 165 lbs by dividing 165 by 2.02.
The answer is approximately 74.91

6 0

3 years ago

Again(sorry) did anyone know 96 and 97

vladimir2022 [97]

96:

sugar: 1,2,3,4,5,6
flour:2,4,6,8,10,12

97:

yellow:3,6,9,12,15,18
blue:1,2,3,4,5,6

7 0

2 years ago

Read 2 more answers

If John pays $144 for 9 pounds of pears, how much is each pound

Artist 52 [7]

Answer:

$16 per pound

Step-by-step explanation:

We want to find the price per pound.

Therefore, we must divide the cost by the pounds.

$\frac{cost}{pounds}$

We know it costs $144 for 9 pounds of pears. Therefore, $144 is the cost and there are 9 pounds.

$\frac{\$144}{9 pounds}$

Divide.

$\$16 /pound$

It costs $16 for each pound of pears.

5 0

3 years ago

Read 2 more answers

W(n) = n + 3; Find the value of w(-5)<br> A) 2 <br> B) -2<br> C) 3<br> D) 1

Lina20 [59]

Answer:

-2

Step-by-step explanation:

-5 + 3 = -2

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)

6 0

3 years ago