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Lostsunrise [7]
2 years ago
8

Can someone please help me find out the answer to this question?

Mathematics
2 answers:
azamat2 years ago
8 0

Answer:

  B.  b(a) = a/6 -9

Step-by-step explanation:

Solve the given equation for b.

  a = 12(b +9)/2

  a = 6(b +9) . . . . simplify

  a/6 = b +9 . . . . divide by 6

  a/6 -9 = b . . . . subtract 9

Then the inverse relation is ...

  b(a) = a/6 -9 . . . . . . . matches choice B

MAXImum [283]2 years ago
5 0

Answer:

its b

Step-by-step explanation:

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Help with this question Asap!! I need all the help I can get!
tankabanditka [31]

Answer:

\large{YES}\ \dfrac{BC}{YZ}=\dfrac{AC}{XY}=\dfrac{AB}{XZ}=\dfrac{2}{1}\\\\\text{and}\ \angle B\cong\angle Z,\ \angle C\cong\angle Y,\ \angle A\cong\angle X

Step-by-step explanation:

BC\to ZY\\AB\to XZ\\AC\to XY\\\angle A\to\angle X\\\angle B\to\angle Z\\\angle C\to\angle Y

\text{We have:}\\\\\triangle ABC:\ AB=20,\ BC=12,\ AC=18\\\triangle XZY:\ XZ=10,\ YZ=6,\ XY=9\\\\\text{check the ratio:}\\\\\dfrac{AB}{XZ}=\dfrac{20}{10}=2\\\\\dfrac{BC}{YZ}=\dfrac{12}{6}=2\\\\\dfrac{AC}{XY}=\dfrac{18}{9}=2\\\\\text{CORRECT :)}\\\\\angle B\cong\angle Z,\ \angle C\cong\angle Y\\\\\text{We know that: The sum of the acute angles in a right triangle is}\ 90^o.\\\\m\angle B+m\angle A=90^o\ \text{and}\ m\angle Z+m\angle X=90^o

\text{We know}\ m\angle B=m\angle Z\to \ m\angle A=m\angle X.\\\text{therefore}\ \angle A\cong\angle X

5 0
3 years ago
if the length of segment AB is 1/3 the length of segment AC and if segment AC is 12 cm long, how long is segment BC?
jeka94
The length of BC I believe will be 8
8 0
3 years ago
Read 2 more answers
The mean of this data set: (5, 8, 1, 7, 4, 3, 2, 2)= 5
Softa [21]

Step-by-step explanation:

4

Add all to get 32

Divide by the number of items which is 8

answer =4

4 0
2 years ago
Read 2 more answers
Mary bought 4 small cookies for 40 cents each and 2 large cookies for 90 cents each how much did she spend all together
babunello [35]

Answer:

$3.40

Step-by-step explanation:

4x.40 is 1.60

2x.90 is 1.80

Then you take 1.80+1.60 to get $3.40 Hope this helps!

4 0
3 years ago
In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

h = \frac{-f'(a) }{f''(a)} ± \frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}

So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

6 0
3 years ago
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