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Lostsunrise [7]

2 years ago

8

Can someone please help me find out the answer to this question?

2 answers:

azamat2 years ago

8 0

Answer:

B. b(a) = a/6 -9

Step-by-step explanation:

Solve the given equation for b.

a = 12(b +9)/2

a = 6(b +9) . . . . simplify

a/6 = b +9 . . . . divide by 6

a/6 -9 = b . . . . subtract 9

Then the inverse relation is ...

b(a) = a/6 -9 . . . . . . . matches choice B

MAXImum [283]2 years ago

5 0

Answer:

its b

Step-by-step explanation:

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Help with this question Asap!! I need all the help I can get!

tankabanditka [31]

Answer:

$\large{YES}\ \dfrac{BC}{YZ}=\dfrac{AC}{XY}=\dfrac{AB}{XZ}=\dfrac{2}{1}\\\\\text{and}\ \angle B\cong\angle Z,\ \angle C\cong\angle Y,\ \angle A\cong\angle X$

Step-by-step explanation:

$BC\to ZY\\AB\to XZ\\AC\to XY\\\angle A\to\angle X\\\angle B\to\angle Z\\\angle C\to\angle Y$

$\text{We have:}\\\\\triangle ABC:\ AB=20,\ BC=12,\ AC=18\\\triangle XZY:\ XZ=10,\ YZ=6,\ XY=9\\\\\text{check the ratio:}\\\\\dfrac{AB}{XZ}=\dfrac{20}{10}=2\\\\\dfrac{BC}{YZ}=\dfrac{12}{6}=2\\\\\dfrac{AC}{XY}=\dfrac{18}{9}=2\\\\\text{CORRECT :)}\\\\\angle B\cong\angle Z,\ \angle C\cong\angle Y\\\\\text{We know that: The sum of the acute angles in a right triangle is}\ 90^o.\\\\m\angle B+m\angle A=90^o\ \text{and}\ m\angle Z+m\angle X=90^o$

$\text{We know}\ m\angle B=m\angle Z\to \ m\angle A=m\angle X.\\\text{therefore}\ \angle A\cong\angle X$

5 0

3 years ago

if the length of segment AB is 1/3 the length of segment AC and if segment AC is 12 cm long, how long is segment BC?

jeka94

The length of BC I believe will be 8

8 0

3 years ago

Read 2 more answers

The mean of this data set: (5, 8, 1, 7, 4, 3, 2, 2)= 5

Softa [21]

Step-by-step explanation:

4

Add all to get 32

Divide by the number of items which is 8

answer =4

4 0

2 years ago

Read 2 more answers

Mary bought 4 small cookies for 40 cents each and 2 large cookies for 90 cents each how much did she spend all together

babunello [35]

Answer:

$3.40

Step-by-step explanation:

4x.40 is 1.60

2x.90 is 1.80

Then you take 1.80+1.60 to get $3.40 Hope this helps!

4 0

3 years ago

In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T

dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + $\frac{h^{2} }{2!}$ f''(a) = 0

$h = \frac{-f'(a) }{f''(a)}$ ± $\frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}$

So, we get the succeeding equation for Newton's method as

$x_{i+1} = x_{i} + \frac{1}{f''x_{i}} [-f'(x_{i})$ ± $\sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]$

Part B.

It is evident that Newton's method fails in two cases, as:

1. if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)

Part C.

In case $x_{i+1}$ is close to $x_{i}$ , the choice that shouldbe made instead of ± in part A is:

f'(x) = $\sqrt{f'(x)^{2} - 2f(x)f''(x)}$ ⇔ $x_{i+1} = x_{i}$

Part D.

As given $x_{i+1}$ = $x_{i}$ = h

or h = $x_{i+1}$ - $x_{i}$

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also, ( $x_{i+1}$ - $x_{i}$ )² = -( $x_{i+1}$ - $x_{i}$ )(f( $x_{i}$ )/f'( $x_{i}$ ))

So, f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also, $x_{i+1}$ = $x_{i}$ -f( $x_{i}$ )/f'( $x_{i}$ ) + [( $x_{i+1}$ - $x_{i}$ )f''( $x_{i}$ )f( $x_{i}$ )]/[2(f'( $x_{i}$ ))²]

6 0

3 years ago