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Oksana_A [137]
2 years ago
10

The map shows regions of Africa, Europe, Asia, and Australia. It also shows a range of deforestation zones in these continents.

On the map, red stands for high deforestation, dark green stands for medium deforestation, blue stands for low deforestation, and pink stands for unavailable data. Identify the areas where species are most at risk of habitat loss.
Biology
1 answer:
Mars2501 [29]2 years ago
6 0

Answer:

Red zone stands for high deforestation.

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A malaria outbreak causing allele frequencies to change is an example of:
julsineya [31]

<u>Answer</u>: Natural selection.

<u>Explanation</u>:

  • The concept of <em>natural selection</em> was given by <em>Charles Darwin.</em>
  • According to this concept, in a given environment the organisms that possess <em>better adaptations</em> have<em> higher chances of survival</em> and, leave behind a <em>greater number of progenies</em>.
  • When malaria outbreak occurs, the allele frequencies change and only the organisms that possess the alleles which help them to <em>survive</em> this outbreak due to resistance against malarial infection will be selected by nature and<em> hence, this is an example of natural selection.</em>
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A biologist whose interest lies primarily in the study of plants or animals can be called a naturalist, although these days it's more likely she'll be called a natural historian, a botanist, or a zoologist.
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3 years ago
Why is latitude a factor in the uneven heating of Earth's surface?​
Maru [420]

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Explanation:

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In 1980, Y. published an extended pedigree of family in which
nydimaria [60]

Answer:

Zero (0)

Explanation:

According to the given information the genotype of the woman with blood type "AB" would by I^AI^B. The genotype of the man with blood type O would be "ii". Here, the alleles I^A and I^B are dominant over the allele "i".

A cross between parents with genotype I^AI^B and ii would give 50% of children with I^Ai genotype and 50% of children with I^Bi genotype. The children with "I^Ai genotype" would have blood type "A" and the children with I^Bi genotype would have blood type "B". This couple is never likely to have any child with blood type "O" since the mother does not carry allele "i".

Cross: I^AI^B x ii = 1/2 I^Ai : 1/2 I^Bi

5 0
3 years ago
Tay-Sachs disease is a lethal, autosomal recessive genetic disorder. If both parents are heterozygous carriers of the disease, w
rjkz [21]

Answer:

50%

Explanation:

Let's assume that the allele "T" gives the normal phenotype while the recessive allele "t" imparts the disease and is lethal in homozygous condition. The genotype of each of the two carrier parents would be "Tt". A cross between Tt and Tt would give the progeny in the following genotype ratio=

Tt x Tt= 1/4 TT: 1/2 Tt: 1/4 tt

Therefore, 1/2 or 50% progeny would be the carrier for the Tay-Sachs disease.

4 0
3 years ago
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