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Whitepunk [10]
3 years ago
8

Explain how scientists manipulate dna

Biology
1 answer:
Sholpan [36]3 years ago
8 0

Scientists manipulate DNA by splitting it apart. They separate the DNA into segments with gel electrocophesis. From there, they can change up the chains and patterns in ways they please.

Answer: By splitting it into segments

walk in someone else's shoes

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Which of the following would likely reduce the threats posed by exotic species to native species?I. Increasing inspections of go
Tamiku [17]

Answer:

A. I only

Explanation:

Exotic animal species are really found in most countries and given that people these animals, they are very valuable. Species like lions, tigers, parrots, cheaters and even pythons are loved for exotic nature.

For this reason, they are caught, killed, shipped and sold in various countries or regions like dubia, Saudi Arabia etc. Its effects on the population of these species are disastrous.

If the inspection of goods coming into a country is intense and frequent, it will mitigate the shipping and sales of the species.

3 0
3 years ago
What does a cost benefit indicate
kramer

That it has higher value than other things being sold.

4 0
3 years ago
Everyone in Squidward’s family has light blue skin, which is the dominant trait for body color in his hometown of Squid Valley.
Colt1911 [192]

All their children will have heterozygous genes because squidward is "purebred", or homozygous dominant. His wife has to be homozygous recessive for a recessive trait to show up. Every time you cross a homozygous dominant trait with a homozygous recessive trait, you will get heterozygous kids. This means all of them will have light blue skin.

6 0
3 years ago
The giant continent which was composed of all the land on Earth was called
irga5000 [103]
The answer is "Pangaea"
8 0
3 years ago
Read 2 more answers
Alkaptonuria is an infrequent autosomal recessive condition. It is first noticed in newborns when the urine in their diapers tur
Arisa [49]

Answer:

See the answer below

Explanation:

Let the disorder be represented by the allele a.

Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.

Since the four adults are carriers, their genotypes would be Aa.

                    Aa     x     Aa

Progeny:    AA    2Aa    aa

Probability of being affected = 1/4

Probability of being a carrier = 1/2

Probability of not being affected = 3/4

(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2

(b) The chance that  the third child of Sara and James will be free of the condition = 3/4

(c)

(d) If someone has no family history of the disorder, their genotype would be AA.

                 AA     x     aa

                        4 Aa

<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0

(e)

(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0

5 0
3 years ago
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