Answer: 3.75 Square Meters
Step-by-step explanation: I am not sure exactly what you asked for here, I chose to take it as the one wall being 5 meters long, and the other being 3/4 meter long. If this was the right senario, then what you would do to solve it, and what I did, is just multiply 5*3/4 or if it makes it simpler, 5*.75
Well, remember we can't take the square root of a negative
so we see that we have

so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]
a. D=[-1,1] or from -1 to 1 is domain
b. for a TI-84, go to y-editor then input

for y1
c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7
A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7
Complete Question
In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
Answer:
16.5°
Step-by-step explanation:
In ΔUVW, w = 9 cm, v = 22 cm and ∠V=136°. Find all possible values of ∠W, to the nearest 10th of a degree.
We solve using Sine rule formula
a/sin A = b/sin B
We are solving for angle W
∠V=136°
Hence:
22 /sin 136 = 9 /sin W
Cross Multiply
22 × sin W = sin 136 × 9
sin W = sin 136 × 9/22
W = arc sin [sin 136 × 9/2.2]
W = 16.50975°
W = 16.5°
Answer:
Try your best! I know you can do it!
The answer is 50º
Step-by-step explanation:
It is the correct and only plausable answer.