I’m not exactly sure what the question is asking, but assuming that the equation is r=10b^2, then the answer would be r=40.
Answer:
$2647.18
Step-by-step explanation:
Formula : ![A[\frac{1+(\frac{r}{n})^{n}-1 }{(\frac{r}{n} )}]](https://tex.z-dn.net/?f=A%5B%5Cfrac%7B1%2B%28%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bn%7D-1%20%7D%7B%28%5Cfrac%7Br%7D%7Bn%7D%20%29%7D%5D)
Future value = $43,000
r = rate of interest = 9% = 0.09
t = 3.5 years (compounded quarterly)
n = number of compounding (3.5 × 4) = 14
Now put the values into formula :
43000 = ![A[\frac{1+(\frac{0.09}{4})^{14}-1 }{(\frac{0.09}{4} )}]](https://tex.z-dn.net/?f=A%5B%5Cfrac%7B1%2B%28%5Cfrac%7B0.09%7D%7B4%7D%29%5E%7B14%7D-1%20%7D%7B%28%5Cfrac%7B0.09%7D%7B4%7D%20%29%7D%5D)
43000=A(
43,000 = A(16.243708)
A = 
A = $2,647.17883 ≈ $2647.18
Answer:
<h3>
m∠BAC = 80° </h3>
Step-by-step explanation:
m∠BCD = 145° ⇒ m∠BCA = 180° - 145° = 35°
From ΔABC:
m∠ABC + m∠BCA + m∠BAC = 180°
65° + 35° + m∠BAC = 180°
m∠BAC = 180° - 100°
m∠BAC = 80°
Answer: The new ratio will be 1/4
Explanation: The initial ratio of losses to wins is 3 to 2. If we sum the numer of losses and wins 3 + 2 = 5 games, that means they loss 3 out of 5 games , and they win 2 out of 5 games.
So if they had won twice as many of the games, that is 2*2=4. And since the number of games is the same ( 5 ), then they would have won 4 games and loss only 1.
So the new ratio of losses to wins will be 1 to 4, or expressed in a fraction: 1/4
