Question

What are the intercepts of x^2 +8x+16​

Answer 1

Answers:

x intercept = -4

y intercept = 16

The graph is shown below.

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Explanation:

To determine the x intercept(s), we set the expression equal to zero and solve for x. In other words, we plug in y = 0 and solve for x.

y = x^2 +8x+16​

0 = x^2 +8x+16​

x^2 +8x+16​ = 0

(x+4)^2 = 0

x+4 = 0

x = -4

There's only one x intercept. It's located at the vertex of the parabola.

The location of the x intercept is the point (-4,0)

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To find the y intercept, we plug in x = 0 and compute like so:

y = x^2 +8x+16​

y = (0)^2 +8(0)+16​

y = 16

The y intercept is 16 which is located at (0,16)

Check out the graph below. It was made using the free app Desmos.