What are the intercepts of x^2 +8x+16
1 answer:
Answers:
x intercept = -4
y intercept = 16
The graph is shown below.
=======================================================
Explanation:
To determine the x intercept(s), we set the expression equal to zero and solve for x. In other words, we plug in y = 0 and solve for x.
y = x^2 +8x+16
0 = x^2 +8x+16
x^2 +8x+16 = 0
(x+4)^2 = 0
x+4 = 0
x = -4
There's only one x intercept. It's located at the vertex of the parabola.
The location of the x intercept is the point (-4,0)
------------
To find the y intercept, we plug in x = 0 and compute like so:
y = x^2 +8x+16
y = (0)^2 +8(0)+16
y = 16
The y intercept is 16 which is located at (0,16)
Check out the graph below. It was made using the free app Desmos.
You might be interested in
Answer:
Common Difference(d) is
Step-by-step explanation:
Given sequence is :
If a sequence has a constant common difference throughout the sequence, then the sequence is called Arithmetic Progression.
Considering a sequence:
where 'd' is the common difference of the A.P.
Similarly, finding the common difference of the given sequence.
Common Difference(d) is