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3 years ago

The figure shown is a semicircle. Find its area. Round your solution to 2 decimal places.

Mathematics

1 answer:

Leona [35]3 years ago

7 0

Answer:

12.5 pie , 39.25 using pie=3.14, and 39.28 to be exact

Step-by-step explanation:

BTW n=pie

10in= Diameter

5in=Radius

Area=n5^2

= 25n/2

=12.5n

12.5 times 3.14= 39.25

22/7 times 12.5= 39.2857143

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Step-by-step explanation:

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4 0

3 years ago

given y>0 and dy/dx=(3x^2+4x)/yif the point (1,√10) is on the graph relating x and y, then what is y when x=0

jonny [76]

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3x^2+4x}y\iff y\,\mathrm dy=(3x^2+4x)\,\mathrm dx$
$\implies\displaystyle\int y\,\mathrm dy=\int(3x^2+4x)\,\mathrm dx$
$\implies \dfrac12y^2=x^3+2x^2+C$

When $x=1$ you have $y=\sqrt{10}$ , so

$\dfrac12(\sqrt{10})^2=1^3+2(1)^2+C\implies 5=1+2+C\implies C=2$

and so the particular solution to the ODE is

$\dfrac12y^2=x^3+2x^2+2$

Then when $x=0$ , you get

$\dfrac12y^2=0^3+2(0)^2+2=2$
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where we omitted the negative root because it's given that $y>0$ .

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3 years ago