Answer:
The first one
Step-by-step explanation:
Answer:
Option B. 5 hours
Step-by-step explanation:
The tennis club charges monthly fees = $50.00
and per hour charges of court time = $10.00
Lets assume you play number of hours in a month = x hr
So, per hour charges would be = $10x
Total payment = monthly charges + charges of played hours
$100.00 = $50.00 + 10x
10x = 100 - 50
10x = 50
x = 5
Option B. You used 5 hours court time.
A relation is a function if the value in its Domain does not occur more than once. This means each domain value is paired with exactly one value of range.
In the given scenario, the domain is the students (e.g name of a student) and the function returns the date of birth of the student. A student can have only one date of birth. So it is not possible that a value in Domain(i.e. a student) is paired with more than one date of births.
Therefore, we can conclude that the given relation describes a function.
23. not equivalent because the first row 3x-9y=5 then if you multiplied this equation by 2 it will be 2(3x-9y) = 2(5) so 6x-18y= 10 not 6x-9y=10
24.equivalent because the second row 2y-6x=8 multiplied by 2 is 2(2y-6x)= 2(8) so 4y-12x=16
25. equivalent because the first row 5x+3y=19 multiplied by 2 is 2(5x+3y) = 2(19) SO 10X+6Y=38 and the second row 2x+4y=20 multiplied by 5 is 5(2x+4y)= 5(20) so 10x+20y=100
I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>