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Fofino [41]
2 years ago
9

Scientists are sending a rover to the moon. Their plan is to study a rectangular area of the moon by placing a grid over the map

as shown. On the grid, 1 unit represents 1 kilometer (km).
the Rover will land at (3.5,1) , explore up to (3.5,4), and then over (2,4).

PART A. what are the coordinates of the fourth vertex of the rectangle that the scientist plan to explore ?

PART B.
what is a horizontal length of the rectangle? what is the vertical length of the rectangle

PART C. find the area of the Moon exploration area in square kilometers. Show your work. ​

Mathematics
1 answer:
Salsk061 [2.6K]2 years ago
4 0

The fourth vertex is (2, 1), and horizontal length is 1.5 km and the vertical length is 3 km. Then the area of the Moon exploration area will be 4.5 square km.

<h3>What is the area of the rectangle?</h3>

Let L be the length and W be the width of the rectangle.

Then the area of the rectangle will be

Area of the rectangle = L×W square units

Scientists are sending a rover to the moon.

Their plan is to study a rectangular area of the moon by placing a grid over the map as shown.

On the grid, 1 unit represents 1 kilometer (km).

PART A.  Then the coordinates of the fourth vertex of the rectangle will be (2, 1).

PART B. Then the horizontal length of the rectangle will be 1.5 km and the vertical length of the rectangle will be 3 km.

PART C. Then the area of the Moon exploration area in square kilometers will be

Area = 3 x 1.5

Area = 4.5 square km

More about the area of the rectangle link is given below.

brainly.com/question/20693059

#SPJ1

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ozzi

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4 0
2 years ago
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Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).
ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

\overrightarrow {PQ}==

\overrightarrow {PR}==

The nonzero vector orthogonal to the plane through the points P,Q, and R is

\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}

\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}

Expand along row 1.

\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}

\overrightarrow n=i(-9)-j(8)+k(2)

\overrightarrow n=-9i-8j+2k

\overrightarrow n=

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

8 0
3 years ago
Help me please quickly.
Vikki [24]

Answer:

M

Step-by-step explanation:

5 comes from point M

I hope this is good enough for you:

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2 years ago
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From left to right it’s 1, 49, 9, 70
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Answer:

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Step-by-step explanation:

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