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Fofino [41]
2 years ago
9

Scientists are sending a rover to the moon. Their plan is to study a rectangular area of the moon by placing a grid over the map

as shown. On the grid, 1 unit represents 1 kilometer (km).
the Rover will land at (3.5,1) , explore up to (3.5,4), and then over (2,4).

PART A. what are the coordinates of the fourth vertex of the rectangle that the scientist plan to explore ?

PART B.
what is a horizontal length of the rectangle? what is the vertical length of the rectangle

PART C. find the area of the Moon exploration area in square kilometers. Show your work. ​

Mathematics
1 answer:
Salsk061 [2.6K]2 years ago
4 0

The fourth vertex is (2, 1), and horizontal length is 1.5 km and the vertical length is 3 km. Then the area of the Moon exploration area will be 4.5 square km.

<h3>What is the area of the rectangle?</h3>

Let L be the length and W be the width of the rectangle.

Then the area of the rectangle will be

Area of the rectangle = L×W square units

Scientists are sending a rover to the moon.

Their plan is to study a rectangular area of the moon by placing a grid over the map as shown.

On the grid, 1 unit represents 1 kilometer (km).

PART A.  Then the coordinates of the fourth vertex of the rectangle will be (2, 1).

PART B. Then the horizontal length of the rectangle will be 1.5 km and the vertical length of the rectangle will be 3 km.

PART C. Then the area of the Moon exploration area in square kilometers will be

Area = 3 x 1.5

Area = 4.5 square km

More about the area of the rectangle link is given below.

brainly.com/question/20693059

#SPJ1

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Can you please help me
puteri [66]

Answer:

The first one

Step-by-step explanation:

4 0
2 years ago
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The tennis club where you play tennis charges $50.00 per month and $10.00 per hour of court time. If your current month's bill i
anyanavicka [17]

Answer:

Option B. 5 hours

Step-by-step explanation:

The tennis club charges monthly fees = $50.00

and per hour charges of court time = $10.00

Lets assume you play number of hours in a month = x hr

So, per hour charges would be = $10x

Total payment = monthly charges + charges of played hours

$100.00 = $50.00 + 10x

10x = 100 - 50

10x = 50

x = 5

Option B. You used 5 hours court time.

7 0
2 years ago
Let D = {x| x is a student} be the domain, and let ƒ(x) = “date of birth” be the possible function. Determine if the relation is
shusha [124]
A relation is a function if the value in its Domain does not occur more than once. This means each domain value is paired with exactly one value of range.

In the given scenario, the domain is the students (e.g name of a student) and the function returns the date of birth of the student. A student can have only one date of birth. So it is not possible that a value in Domain(i.e. a student) is paired with more than one date of births. 

Therefore, we can conclude that the given relation describes a function. 
5 0
3 years ago
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Can someone help me with this and explain it to me please? :)<br><br> CHECK ATTACHED
babymother [125]
23. not equivalent because the first row 3x-9y=5 then if you multiplied this equation by 2 it will be 2(3x-9y) = 2(5) so 6x-18y= 10 not 6x-9y=10


24.equivalent because the second row 2y-6x=8 multiplied by 2 is 2(2y-6x)= 2(8) so 4y-12x=16

25. equivalent because the first row 5x+3y=19 multiplied by 2 is 2(5x+3y) = 2(19) SO 10X+6Y=38 and the second row 2x+4y=20 multiplied by 5 is 5(2x+4y)= 5(20) so 10x+20y=100
4 0
3 years ago
Y=x² + 16x + 64
motikmotik

I'll do the first one to get you started

The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64

Compare that to y = ax^2+bx+c and we see that

a = 1

b = 16

c = 64

Use the values of 'a' and b to get the value of h as shown below

h = -b/(2a)

h = -16/(2*1)

h = -8

This is the x coordinate of the vertex.

Plug this x value into the original equation to find the corresponding y value of the vertex.

y = x^2+16x+64

y = (-8)^2 + 16(-8) + 64

y = 0

Since the y coordinate of the vertex is 0, this means k = 0.

The vertex is (h,k) = (-8, 0)

---------------------

So we found that a = 1, h = -8 and k = 0

Therefore,

f(x) = a(x-h)^2 + k

f(x) = 1(x-(-8))^2 + 0

f(x) = (x+8)^2

is the vertex form

---------------------

<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
8 0
3 years ago
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