1 joule = 6,242e+18ev
20 joule = 20 joule *6,242e+18 ev/joule =1,248e+20 ev
1,248e+20 ev / (10 ev / photon) =1,248e+19 photons.
You can solve this problem by applying the proccedure below:
You have:
a) 18/21=2/3
18x3/21x2
36≠42 (2/3 is not proportinal to 18/21).
b)18/21=30/35
18x35/21x30
630=630 (30/35 is proportional to 18/21)
c)18/21=36/48
18x48/21x36
864≠756 (36/48<span> is</span><span> not proportinal to 18/21)
</span>
d)18/21=1/3
18x3/21x1
54≠21 (<span> 1/3 is</span><span> not proportinal to 18/21)
</span>
Therefore, you can conclude that the correct option is: B.30/35
• Imagine we are using these two points to draw a triangle where new point E is a right angle with coordinates (-1, -9)
• FE = 5
• EC = 4
• FE^2 + EC^2 = FC^2
• (25) + (16) = 41 = FC^2
• FC = square root(41)
Answer:
200 pairs of sandals
Step-by-step explanation:
Represent the sandals with x and the running shoes with y.
In a typical month:
In April
Required
The number of sandals in a typical month
<u>In a typical month:</u>
If 1 sandal costs 2.50, then x costs 2.50x
If 1 running shoe costs 4, then y costs 4y
The total is:
<u>In April:</u>
If 1 sandal costs 2.50, then 2x costs 5x ---- <em>we used 2x because the pairs is doubled </em>
If 1 running shoe costs 4, then y costs 4y
The total is:
The equations are:
Subtract
18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).
Answer: B]
20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3
21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]
