If a/b-d=2c/b find the value of c when a=3, b=4 and d=-5

Mathematics

2 answers:

Elena-2011 [213]3 years ago

5 0

It’s either 2/3 or 11.5 depending on where the d is lol

Mice21 [21]3 years ago

4 0

I’m answering so u can mark the girl brainliest

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A population of size 320 has a proportion equal to .60 for the characteristic of interest. What are the mean and the standard de

tiny-mole [99]

Answer:

The answer is c.) 0.6 and 0.14

Step-by-step explanation:

Given population has a size of 320.

The proportion of population = 0.6

The mean of population, p = 0.6

The mean of sample, $\hat{p}$ = 0.6

Therefore $\hat{q}$ = 1 - $\hat{p}$ = 1 - 0.6 = 0.4

The sample size = 12

Therefore the standard deviation of the sample,

$s = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n} } = \sqrt{\frac{0.6 \times 0.4}{12} } = 0.1414$

The mean and the standard deviation for a sample size of 12 are 0.6 and 0.14 respectively.

The answer is c.) 0.6 and 0.14

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Identify the initial value in each formula below, and state whether the formula models exponential growth or

Hitman42 [59]

Answer: Hello mate!

the equation is written is:

f(t) = 2 / 3 (3)t

And is hard to work with this, but let's try:

I will interpret this function in two ways:

f(t) = (2/3^(3t)) in this case, the exponential part is in the denominator, so when t increases, the denominator also increases, if the denominator increases, the value of the function decreases, then, in this case, we have an exponential decay.

second case:

f(t) = (2/3)^(3t) the case is similar.

we know that 2/3 < 1

now, (2/3)^3t = (2^3t/3^3t)

3 is a number bigger than 2, then 3^3t > 2^3t, meaning that when t increases, bot denominator, and numerator increases, but the denominator increases faster, this means that we still have an exponential decay.

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leonid [27]

It would be 32*15*2.80

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