$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{ - 5 + - \sqrt{ {5}^{2} - 4(5) } }{2} \\ x = \frac{ - 5 + - \sqrt{25 - 20} }{2} \\ x = \frac{ - 5 + - \sqrt{5} }{2}$

Therefore, the zeroes would be:

$x1 = \frac{ - 5 + \sqrt{5} }{2} \\ x2 = \frac{ - 5 - \sqrt{5} }{2}$

8 0

3 years ago

Which of the I-values are solutions to both of the following inequalities?

lidiya [134]

Answer:

Option (C)

Step-by-step explanation:

Given inequalities are,

81 > x and x > 68

Therefore, 81 > x > 68 is the inequality representing the solution area for x.

Out of x = 88, 85 and 80,

x = 80 will lie between the range of x = 68 and x = 81.

Therefore, Option (C) will be the correct option.

5 0

3 years ago

Can Somebody Please Help Me Understand This?! Thanks

DiKsa [7]

Answer:

Step-by-step explanation:

It's A

5 0

3 years ago

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