Question

To increase sales, an online clothing store began giving a 50% off coupon to random customers. Customers didn't know whether they would receive the coupon until after the final sale. The website claimed that one in five customers received the coupon. Six customers each made purchases from the website. Let X = the number of customers that received the 50% off coupon.

Answer 1

To increase sales, an online clothing store began giving a 50% off coupon to random customers Six customers each made purchases from the website the binomial random variable and  mean and standard deviation of X  is mathematically given as

$X ~ Bin(n = 6, p = 0.2)$

x= 0.9798

What is a binomial random variable?

Generally, the equation for is mathematically given as

P(coupon) = 1/5

P(coupon)= 0.2

the binomial distribution

$X ~ Bin(n = 6, p = 0.2)$

Therefore, The mean and standard deviation of X

$пВ = np \\np= 6* 0.2 = 1.2$

$x=\sqrt{ np(1 - p)} \\ x=\sqrt{ 6 * 0.2 + (1 -0.2)}$

x= 0.9798

In conclusion, mean and standard deviation of X

x= 0.9798

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