To increase sales, an online clothing store began giving a 50% off coupon to random customers. Customers didn't know whether the

Question

2 years ago

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To increase sales, an online clothing store began giving a 50% off coupon to random customers. Customers didn't know whether the

y would receive the coupon until after the final sale. The website claimed that one in five customers received the coupon. Six customers each made purchases from the website. Let X = the number of customers that received the 50% off coupon.

Mathematics

1 answer:

ludmilkaskok [199] · Answer 1 · 2023-10-29T03:49:57+03:00

To increase sales, an online clothing store began giving a 50% off coupon to random customers Six customers each made purchases from the website the binomial random variable and mean and standard deviation of X is mathematically given as

$X ~ Bin(n = 6, p = 0.2)$

x= 0.9798

<h3>What is a binomial random variable?</h3>

Generally, the equation for is mathematically given as

P(coupon) = 1/5

P(coupon)= 0.2

the binomial distribution

$X ~ Bin(n = 6, p = 0.2)$

Therefore, The mean and standard deviation of X

$пВ = np \\np= 6* 0.2 = 1.2\\$

$x=\sqrt{ np(1 - p)} \\ x=\sqrt{ 6 * 0.2 + (1 -0.2)} \\$

x= 0.9798

In conclusion, mean and standard deviation of X

x= 0.9798