Answer: d
Step-by-step explanation:
3xy
<span>y(3y)/3xy + y(xy)/3xy + (y+1)(3x)/3xy </span>
<span>NOW since all of the fractions have a denominator of 3xy, drop the denominators and solve using the numerators. </span>
<span>y(3y) + y(xy) + (y+1)(3x) </span>
<span>3y^2 + xy^2 + 3xy +3x </span>
<span>cannot simplify further.</span>
For two triangles to be congruent by AAS:
1- Two angles in the first triangle must be equal to two angles in the second triangle
2- A non included side in the first triangle is equal to a non included side in the second triangle
Now, let's check our options. We will find that:
For the two triangles UTV and ABC:
angle T = angle A
angle V = angle C
TU (non-included between angles T & V) = AB (non-included between angles A & C)
Therefore, we can conclude that:
Triangles ABC and UTV are congruent by AAS
I think you mean six-hundred and seventy six.
6 ÷ 576 = 0.010416
or 0.0104166667
We have x and y intercept:
(2, 0) and (0, 3).
Substitute the coordinates of points to the equation:
