Will give brainliest The question is on the picture

what is the slope and equation of a line that is perpendicular to the y-axis passing through (-5,-3)?

Illusion [34]

Answer:

Slope is m=0

$y=-3$

Step-by-step explanation:

The slope of any line that is perpendicular to the y-axis is zero.

The reason is that any line that is perpendicular to the y-axis is also parallel to the x-axis and the slope of the x-axis is zero.

The equation of any line perpendicular to the y-axis is and passes through (a,b) is y=b.

The given point is (-5,-3) hence the required equation is

$y=-3$

3 0

2 years ago

Find the value of x that will make L||M. Please help me on this one!!!!!!! I need this done.

Galina-37 [17]

The given angles are known as alternate interior angles.

For line L and M to be parallel, the two given angles must be the same.

Set them to equal each other and solve for X.

7x - 7 = 4x +14

Add 7 to each side:

7x = 4x +21

Subtract 4x from each side"

3x = 21

Divide both sides by 3:

X = 21 / 3

X = 7

5 0

3 years ago

Read 2 more answers

If the original pair of a pair of shoes is $80 but a sign above the shoes reads “ Sale - 20% discount”, then what price would a

solong [7]

Answer:

A. 64

Step-by-step explanation:

The shoes are 80 dollars. We get a 20% discount

Discount = 80*20%

= 80*.20

=16

The sales price = original price less the discount

= 80 -16

= 64

6 0

3 years ago

The length of a rectangle is 5in longer than its width. If the perimeter of the rectangle is 46in, find its area

Crank

width = x
length = x+5

2x + 2(x+5) = 46
2x + 2x + 10 = 46
4x = 46 - 10
4x = 36
x = 36/4 
x = 9 in ← width

length = x+5 = 9 + 5 = 14 in

Area = 9 * 14 = 126 in²

6 0

3 years ago

Based on the Nielsen ratings, the local CBS affiliate claims its 11:00 PM newscast reaches 41 % of the viewing audience in the a

ZanzabumX [31]

Answer:

1) Null hypothesis: $p\geq 0.41$

Alternative hypothesis: $p < 0.41$

2) $\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

3) $z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

4) $z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

5) $z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

6) We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

7) Null hypothesis: $p\geq 0.41$

Step-by-step explanation:

Data given and notation

n=100 represent the random sample taken

X represent the people indicated that they watch the late evening news on this local CBS station

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

$p_o=0.41$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) Part 1We need to conduct a hypothesis in order to test the claim that 11:00 PM newscast reaches 41 % of the viewing audience in the area: Null hypothesis:[tex]p\geq 0.41$

Alternative hypothesis: $p < 0.41$

Part 2

$\hat p=0.36$ estimated proportion of people indicated that they watch the late evening news on this local CBS station

Part 3

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :

$z_{crit}=-2.33$

And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"

Part 4

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.36 -0.41}{\sqrt{\frac{0.41(1-0.41)}{1000}}}=-1.017$

Part 5

Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :

$z_{crit}=-1.28$

And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"

Part 6

We see that $|t_{calculated}|$ so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.

Part 7

Null hypothesis: $p\geq 0.41$

4 0

2 years ago