You can factor out a 3t first, resulting in:
Now, let's factor the equation in the middle using the quadratic equation. Plug in the values to the quadratic equation:
Simplify, you get your
x's:
To write the equation in simplified form, you just write it this way:
That's your answer ^
Answer: 2.266666667
Step-by-step explanation: 34/15=2.266666667
To solve this problem you must apply the proccedure shown below:
1. You have that the <span>parabola is 12 meters high at the vertex and at a height of 10 meters, the width is 8 meter.
2. Therefore, you have:
x^2=-4a(y^2-k)
4</span>^2=-4a(10-12)
16=-40a+48
16=8a
a=16/8
a=2
y=0
x^2=-8(0-12)
x^2=96
x=√96
x=9.79x2
x=19.58
3. Therefore, as you can see, the answer is: 19.58 meters.<span>
</span>
Answer:
7.8-9.3n
Step-by-step explanation:
2.8-5.3n - 4n + 5
Combine like terms
2.8 +5 -5.3n -4n
7.8-9.3n
Answer:
Largest Median: Same
Largest Range: Castro
Largest IQR: Castro
Step-by-step explanation:
With a box-and-whisker plot, the box represents the upper and lower quartiles, the vertical line inside the box represents the median, and the lines on either side of the box show the high and low of the range.
Largest Median: Medians are the same because the verticle line inside the boxes is at 7 for both
Largest Range: Ms Castro's Class- the lines on either side of the box for Ms Castro go from 1-10 while the other class only goes from 4-10.
Largest IQR (interquartile range) Ms. Castro's class: their IQR goes from 5-8 while the other class only goes from 6-8
