Will give brainliest <br> The question is on the picture

yulyashka [42]

Answer: hypotenuse=16

Step-by-step explanation:

First, you need to know the concept of a special triangle 30-60-90. The corresponding ratio of each side is 1-√3-2. Basically means, the shortest side is 1, the other longer leg is √3, the hypotenuse is 2. You can also refer to the attachment below

For this question, given the shortest side is 8, and asked to find the hypotenuse.

Short side:hypotenuse=1:2

8:hypotenuse=1:2

hypotenuse=16

Hope this helps!! :)

Please let me know if you have any questions

6 0

3 years ago

What is 23,465 rounded to the nearest ten thousand

skad [1K]

Answer:

20,000

Step-by-step explanation:

Scince 4, (a number lower than 5) is in front of the 3 (which is in the 10,000's place), 20,000 should be the answer.

4 0

4 years ago

CAN SOMEONE ANSWER THIS PLEASE AND RHANK YOU!

leonid [27]

Answer:

1/9?

Step-by-step explanation:

8 0

3 years ago

A fourth-order polynomial passes through the five points for which the independent and dependent variables, x and y, respectivel

Sladkaya [172]

Answer:

The fourth-order polynomial that passes through the points is $P(x)=2x^4+x^3+3x^2+2x+5$

Step-by-step explanation:

A fourth-order polynomial has this general form:

$P(x)=ax^4+bx^3+cx^2+dx+e$

We need to replace the given points one by one, which leads to a system of 5 equations and 5 variables (namely a,b,c,d,e)

$37=a(-2)^4+b(-2)^3+c(-2)^2+d(-2)+e\\7=a(-1)^4+b(-1)^3+c(-1)^2+d(-1)+e\\5=a(0)^4+b(0)^3+c(0)^2+d(0)+e\\13=a(1)^4+b(1)^3+c(1)^2+d(1)+e\\61=a(2)^4+b(2)^3+c(2)^2+d(2)+e$

We can rewrite this system as follows:

$16a-8b+4c-2d+e=37\\a-b+c-d+e=7\\e=5\\a+b+c+d+e=13\\16a+8b+4c+2d+e=61$

We can use the Gaussian Elimination to solve this system of equations. To use the Gaussian Elimination we need to express the system of linear equations in matrix form (the matrix equation Ax = b).

The coefficient matrix (A) for the above system is

$\left[\begin{array}{ccccc}16&-8&4&-2&1\\1&-1&1&-1&1\\0&0&0&0&1\\1&1&1&1&1\\16&8&4&2&1\end{array}\right]$

the variable matrix (x) is

$\left[\begin{array}{c}a&b&c&d&e\end{array}\right]$

and the constant matrix (b) is

$\left[\begin{array}{c}37&7&5&13&61\end{array}\right]$

The augmented matrix for this system, it is obtained by appending the columns of the coefficient matrix and the constant matrix.

$\left[\begin{array}{ccccc|c}16&-8&4&-2&1&37\\1&-1&1&-1&1&7\\0&0&0&0&1&5\\1&1&1&1&1&13\\16&8&4&2&1&61\end{array}\right]$

The augmented matrix can be transformed by a sequence of elementary row operations to the reduced row echelon form.

$\left[\begin{array}{ccccc|c}1&0&0&0&0&2\\0&1&0&0&0&1\\0&0&1&0&0&3\\0&0&0&1&0&2\\0&0&0&0&1&5\end{array}\right]$

Therefore the solutions are:

$\left\begin{array}{c}a=2&b=1&c=3&d=2&e=5\end{array}\right$

And the polynomial P(x) is:

$P(x)=2x^4+x^3+3x^2+2x+5$

We can check our solution plotting the polynomial and checking that it passes through the points.

4 0

3 years ago

Someone please help me w this standard form question

svp [43]

Answer:

2.4 × 10⁶

Step-by-step explanation:

Given:

$\sf x=3.8 \times 10^5$

$\sf y=5.9 \times 10^4$

To calculate the value of R, substitute the given values into the given formula:

$\begin{aligned}\sf R & = \sf \dfrac{x^2}{y}\\\\ \implies \sf R& = \sf \dfrac{(3.8 \times 10^5)^2}{5.9 \times 10^4}\\\\& = \sf \dfrac{3.8^2 \times (10^5)^2}{5.9 \times 10^4}\\\\& = \sf \dfrac{14.44 \times 10^{10}}{5.9 \times 10^4}\\\\& = \sf \dfrac{14.44}{5.9} \times \dfrac{10^{10}}{10^4}\\\\& = \sf 2.4474... \times 10^{(10-4)}\\\\& = \sf 2.4474... \times 10^6\\\\\end{aligned}$

Therefore, the value of R to 1 decimal place is 2.4 × 10⁶

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<u>Exponent Rules used</u>

$(a^b)^c=a^{bc}$

${a^b}{a^c}=a^{b-c}$

3 0

2 years ago

Read 2 more answers

Will give brainliest The question is on the picture